Adult tickets cost $4 more than student tickets, if you know that Robert bought 5, then you can multiply 5x4. You can then subtract those $20 from the total of $104, which would bring you to a total of $84. Then you can add the the 5 adult tickets to the 7 student tickets, which would give you a total of 12 tickets. You can then do 84/12= 7 since the cost of every ticket is now equal. Add 4 to the 7 for the cost of the adult ticket. You now have $11 as the cost of an adult ticket and $7 as the cost of a student ticket. Plug everything in to 5a + 7s = 104 if you want to verify the answers. ( a=adult, s=student)
3 hours and also is there supposed to be a dollar sign before 2200
He needs to work 64.5hrs.
Just divide the number needed by the rate.
Answer:
8/11.
Step-by-step explanation:
There are a total of 11 balls.
At least one of those picked is green means that 1 or 2 green balls are picked in the two trials.
Prob (First one picked is green) = 5/11.
Prob( second one picked is green) = 4/10 = 2/5.
Therefore Prob ( Green then green) = 5/11 * 2/5 = 10/55 = 2/11.
The other possibilities are Green then Yellow OR Yellow then Green.
The probabilities of these are worked out as above and come to
5/11 * 6/10 and 6/11 * 5/10
= 300/110 and 30/110
= 3/11 and 3/11.
Finally the Prob ( 2G OR G&Y OR Y&G) = 2/11 + 3/11 + 3/11
= 8/11.
I just realised there is an easier way to do this. Much less work.
The only other thing that can happen other than ' at least one green' is '2 yellows' so the required probability is
1 - prob(2 yellows)
= 1 - (6/11 * 5/10)
= 1 - 30 /110)
= 1 - 3/11
= 8/11.
But never mind. I hope the above is instructive and helps you understand.
True because u can always add or multiply to join groups