19539 bacteria will be present after 18 hours
<u>Solution:</u>
Initial value of bacteria N = 6000
Value after 4 hours 
= 7800
<em><u>The standard exponential equation is given as:</u></em>
where
N is amount after time t
No is the initial amount
k is the constant rate of growth
t is time
Plugging in the values in formula we get,
Solving for "k" we get,
Taking "ln" on both sides, we get
On solving for ln, we get k = -0.0656
The equation becomes, 
Now put "t" = 18,
Hence the bacteria present after 18 hours is 19539
Answer:
Step-by-step explanation:
2/-3 is the answer mark me as brainliest
Yes, 14 is correct.
15: 3^4 - 4
16: 7n - 6
17: n^2 / 8
18: 3n x 9
Therefore, the equation that best fits these facts as the answer to this problem is y=661-0.1x.
<h3 /><h3>Describe a scatter plot.</h3>
The term "scatter plot" refers to a particular sort of graph in which the x- and y-axes are used to represent the values of two variables, with the dots that arise indicating any association between the data.
Given the correlation between the data at this moment and the graph provided in the question, y=661-0.1x is an equation that best captures the scatterplot's line of best fit.
y=661-0.1x is the equation whose solution best fits this data.
To know more about scatter plot , visit
brainly.com/question/2655543
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