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Pepsi [2]
4 years ago
12

Find the length of each hypotenuse such that 2004-02-02-05-00_files/i0200001.jpg

Mathematics
1 answer:
jekas [21]4 years ago
3 0
If the triangles KMN and LMN are congruent:
3 x + y = x + 2 y
8 x - 7 = 5 x + 3 y
------------------------
2 x - 3 y = 0 / · (-1)
3 x - 3 y = 7
----------------------
- 2 x + 3 y = 0
+
3 x - 3 y = 7
---------------------
x = 7,
Hypotenuse KN = LN = 8 · 7 - 7 = 56 - 7 = 49 
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A pair of equations is shown below:
horrorfan [7]

Answer:

A. x=2, y = 7.

B. (2, 7).

Step-by-step explanation:

A. You can eliminate y by subtracting the equations:

y =  8x - 9

y =  4x - 1       Subtract:

0 =  4x - 8

4x = 8

x = 8/4 = 2.

Now substitute for x in the first equation:

y = 8(2) - 9 = 7.

Check in the second equation:

y = 4x - 1

7 = 4(2) - 1 = 7.  Check is OK.

B. On the graph they will intersect at the point (2, 7).

They will intersect here because the values x=2 and y=7 satisfy both the 2 equations.

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If the density of a full can is 1.1g/cc what is it’s mass?
podryga [215]
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coldgirl [10]

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Derive the equation of the parabola with a focus at (−5, −5) and a directrix of y = 7
WARRIOR [948]

Answer: The equation of the parabola is (x+5)^2=-24(y-1).

Explanation:

It is given that the focus of the parabola is (-5,-5) and the directrix is y=7.

The standard form of the parabola is,

(x-h)^2=4p(y-k)

Where y=k-p is directrix and (h,k+p) is the focus.

Since focus is given,

(h,k+p)=(-5,-5)

On comparing,

h=-5

k+p=-5      .... (1)

The directrix is y=7.

k+p=7       .... (2)

Add equation (1) and (2),

2k=2

k=1

Put this value in (1).

p=-6

Put p= -6, h= -5 and k=1 in the standard form of the parabola.

(x+5)^2=4(-6)(y-1)

(x+5)^2=-24(y-1)

Therefore, the equation of parabola is (x+5)^2=-24(y-1).

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