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Ivahew [28]
2 years ago
7

Please help me with this, anything is appriciated!! ^^

Mathematics
1 answer:
Papessa [141]2 years ago
5 0

Answer:

978-78-345=555 so 555/978

Step-by-step explanation:

subtract the number of pages that have been read. the fraction you have left is the number left to read over the total.

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O A PQR is reflected over the x-axis. What are the<br> coordinates of O'?
topjm [15]

Answer:

(8,-2)

Step-by-step explanation:

When reflecting something across the X axis the y axis coordinate is the one that will change to put the position further up or down.  In this case we are moving it down to the same amount below the axis that it is now above it.  That means that since it is currently 2 above the X axis it would then be 2 below the X axis making it at -2 so the coordinates would be (8,-2)

I hope this helps and please don't hesitate to ask if there is anything still unclear!

7 0
3 years ago
Read 2 more answers
In the spring, the owner of a sporting goods store decreases the price of winter gloves from $10.00 to $8.00. She increases the
TEA [102]

Answer:

without doing the math, we can affirm that the percent in decrease in the price of the gloves is <u>not</u> the same as the percent increase of the goggles. decreasing $2 from $10 will have a lower decrease than an increase of $2 from $8 since $2 represents a higher portion of $8 compared to $10

Step-by-step explanation:

(please give brainliest, much appreciated)

6 0
2 years ago
Questions (no partial grades if you don't show your work) 1. In a group of 6 boys and 4 girls, four children are to be selected.
mariarad [96]

Answer:

Total number of ways will be 209

Step-by-step explanation:

There are 6 boys and 4 girls in a group and 4 children are to be selected.

We have to find the number of ways that 4 children can be selected if at least one boy must be in the group of 4.

So the groups can be arranged as

(1 Boy + 3 girls), (2 Boy + 2 girls), (3 Boys + 1 girl), (4 boys)

Now we will find the combinations in which these arrangements can be done.

1 Boy and 3 girls = ^{6}C_{1}\times^{4}C_{3}=6\times4=24

2 Boy and 2 girls=^{6}C_{2}\times^{4}C_{2}=\frac{6!}{4!\times2!}\times\frac{4!}{2!\times2!}=15\times6=90

3 Boys and 1 girl = ^{6}C_{3}\times^{4}C_{1}=\frac{6!}{4!\times2!}\times\frac{4!}{3!}=\frac{6\times5\times4}{3 \times2} \times4=80

4 Boys = ^{6}C_{4}=\frac{6!}{4!\times2!} =\frac{6\times 5}{2\times1}=15

Now total number of ways = 24 + 90 + 80 + 15 = 209

7 0
3 years ago
What are the solutions of the equation (x-3)^2 + 2(x-3) -8 = 0
Mariulka [41]
Expand and simplify
(x-3) (x-3) +2(x-3) -8=0
(x-3+2)(x-3)-8=0
(x-1)(x-3)-8=0
x^2 -4x +3-8=0
x^2 - 4x -5=0
x^2 -5x +x-5=0
x(x-5)+x-5=0
(x+1)(x-5)=0
x= - 1, 5
6 0
3 years ago
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Evaluate 1.1.075 + 21.67 <br> 3.15<br> ​
o-na [289]

Answer:

√ 96

log

(100 )

3 ^5 / 3

Step-by-step explanation:

6 0
3 years ago
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