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ludmilkaskok [199]
2 years ago
12

There are 4 jacks and 13 clubs in a standard, 52-card deck of playing cards. What is the probability that a card picked at rando

m from a standard deck of playing cards is a club or a jack?
A. 7/26
B. 4/13
C. 1/52
D. 3/13
Mathematics
2 answers:
Zigmanuir [339]2 years ago
7 0

Answer:

the answer is D. 4/13 on plato

Tju [1.3M]2 years ago
3 0

With 4 jacks in the deck of 52, there is a 4/52 = 1/13 probability of drawing 1 jack.

With 13 clubs in the deck, there is a 13/52 = 1/4 probability of drawing 1 card of clubs.

1 of the cards in the deck is both a jack and of suit of clubs, which has a 1/52 probability of being drawn.

P(club OR jack) = P(club) + P(jack) - P(club AND jack) = 13/52 + 4/52 - 1/52 = 16/52 = 4/13

So the answer is B.

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A 0 will make the right decision
3 0
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2000x100 guesss yall
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Answer:

200,000

Step-by-step explanation:

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I need help pls A certain university in the United States has a student enrollment of 19,100. Mr. Hill knows the percentage of s
Airida [17]

Answer:

About 8595 students

Step-by-step explanation:

If approximately 9/20 of the students are male, multiplying this by the total number of students enrolled will give a good approximation of the total number of enrolled males. 9/20 * 19100=8595. Hope this helps!

4 0
3 years ago
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Can someone tell me how to do this? with steps?
MrRa [10]

Answer:

Step-by-step explanation:

In Δ AFB,

∠AFB + ∠ABF + ∠A = 180   {Angle sum property of triangle}

90 + 48 + ∠1 = 180

       138 + ∠1 = 180

                 ∠1 = 180 - 138

∠1 = 42°

FC // ED and FD is transversal

So, ∠CFD ≅∠EDF   {Alternate interior angles are congruent}

     ∠2 = 39°

In ΔFCD,

∠2 + ∠3 + ∠FCD = 180

39 + ∠3 + 90 = 180

         129 +∠3 = 180

                   ∠3 = 180- 129

∠3 = 51°    

3 0
2 years ago
Find the surface area of the composite figure. Round to the nearest square centimeter
Goryan [66]

Answer:

Surface area = 726 cm²

None of the options is correct.

Step-by-step explanation:

Surface area of the composite figure = surface area of cone + surface area of cylinder - 2(area of base of cone)

✔️Surface area of cone = πr(r + l)

Where,

Radius (r) = 5 cm

Slant height (l) = √(10² + 5²) (Pythagorean theorem)

Slant height (l) = 11.2 cm

Plug in the values

= π*5(5 + 11.2)

= 254.5 cm²

✔️Surface area of the cylinder = 2πr(h + r)

r = 5 cm

h = 15 cm

Plug in the values into the formula

S.A = 2*π*5(15 + 5)

S.A = 628.3 cm²

✔️area of base of cone = πr²

r = 5 cm

Area = π*5² = 78.5 cm²

✅Surface area of the composite figure = 254.5 + 628.3 - 2(78.5)

= 882.8 - 157

= 726 cm² (nearest square meter)

None of the options is correct.

7 0
3 years ago
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