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DanielleElmas [232]
3 years ago
12

Glucose labeled with 14C in C-3 and C-4 is completely converted to acetyl-CoA via glycolysis and the pyruvate dehydrogenase comp

lex. What percentage of the acetyl-CoA molecules formed will be labeled with 14C, and in which position of the acetyl moiety will the 14c label be found?
a) 100% of the acetyl-CoA will be labeled at C-1 (carboxyl).
b) 100% of the acetyl-CoA will be labeled at C-2
c) 50% of the acetyl-CoAwill be labeled, all at C-2 (methyl).
d) No label will be found in the acetyl-CoA molecule
e) Not enough information is given to answer this question.
Biology
1 answer:
Morgarella [4.7K]3 years ago
5 0

Answer:

The correct answer is option d.

Explanation:

The production of Acetyl-CoA takes place by the dissociation of both carbohydrates and lipids in the process of glycolysis and beta-oxidation. It then moves into the TCA cycle in the mitochondria and combines with oxaloacetate to give rise to citrate.  

In the given case, no labeling will be found in the acetyl-CoA. The labeled C3 and C4 carbon of glucose signify the carboxyl carbon of pyruvate. In the succeeding reactions of the transformation of pyruvate to acetyl-CoA, the carboxyl carbon gets lost in the form of carbon dioxide. Thus, acetyl-CoA does not comprise any labeled C3 and C4 of glucose.  

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