What's the answer tell the truth plz

Help please! 50 Points! PLEASE DONT RESPOND IF YOU DO NOT KNOW.

Sphinxa [80]

Answer:

e.869.58units^2

f. 96m^2

g. 184m^2

Step-by-step explanation:

e.

484 square

176 triangle

209.58 equilateral triangle

f. 196 total are - mini square 25+25+25+25= 96m^2

g. 22+66+80+16=184m^2

3 0

3 years ago

Lucas deposits $4,000.00 for 6 years at 2% interest, compounded monthly. How much interest does he earn at the end of the 6 year

Rudik [331]

Answer:

$12644.56

Step-by-step explanation:

one year = 12 month

4,000 * (1.02)^(6*12) = 16644.5615

16644.5615-4000 = 12644.5615

6 0

3 years ago

Read 2 more answers

A baker purchases flour each week from a wholesale warehouse. The chart shows the quantities and prices available this week. If

scZoUnD [109]

The chart showing the quantities and prices is;

Best Deal 1

Quantity of Flour Price

3 pounds $5.25

5 pounds $9.75

7 pounds $12.60

10 pounds $14.20

12 pounds $18.24

Answer:

difference between last weeks best deal = $0.3

Step-by-step explanation:

Let's calculate the unit price for each of the quantities in the chart.

For quantity of 3 pounds;

We have; unit price = 5.25/3 = $1.75

For 5 pounds;. Unit price = 9.75/5 = $1.95

For 7 pounds; unit price = 12.6/7 = $1.8

For 10 pounds; unit price = 14.2/10 = $1.42

For 12 pounds; unit price = 18.24/14 = $1.3

Thus, last weeks best deal is the lowest = $1.3

Thus; difference between last weeks best deal is given as;

= this weeks best deal - last weeks best deal

This gives;

$1.6 - $1.3 = $0.3

6 0

3 years ago

What is the I will mark you branilst

kolezko [41]

Answer: C the first one

Step-by-step explanation:

8 0

3 years ago

A study by the Pew Research Center1 reports that in 2010, for the first time, more adults aged 18 to 29 got their news from the

sergejj [24]

Answer:

Null hypothesis: $p \leq 0.65$

Alternative hypothesis: $p > 0.65$

$z=\frac{0.66 -0.65}{\sqrt{\frac{0.65(1-0.65)}{1500}}}=0.812$

$p_v =2*P(z>0.812)=0.208$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion it's not significantly higher from 0.65.

We don't have enough evidence to conclude that the true % it's higher than 65%, since we fail to reject the null hypothesis on this case.

Step-by-step explanation:

1) Data given and notation

n=1500 represent the random sample taken

X represent the adults that said television was one of their main sources of news.

$\hat p=0.66$ estimated proportion of adults that said television was one of their main sources of news.

$p_o=0.65$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is higher than 0.65:

Null hypothesis: $p \leq 0.65$

Alternative hypothesis: $p > 0.65$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.66 -0.65}{\sqrt{\frac{0.65(1-0.65)}{1500}}}=0.812$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>0.812)=0.208$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion it's not significantly higher from 0.65.

Do we find evidence that more than 65% of all US adults use television as one of their main sources for news?

We don't have enough evidence to conclude that the true % it's higher than 65%, since we fail to reject the null hypothesis on this case.

6 0

3 years ago