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Keith_Richards [23]
4 years ago
9

What's the answer tell the truth plz

Mathematics
1 answer:
monitta4 years ago
7 0
There are 3 feet in every yard. So, divide each value by 3

120/3 = 40 yards in width

150/3 = 50 yards in length 

Number 3 is the answer
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Find the slope of the line on the graph. Write your answer as a fraction or a whole number, not mixed number or decimal.
Vesna [10]

Answer:

<em>The slope is:</em>

m=-\frac{3}{2}

Step-by-step explanation:

The slope m of a line is calculated using the following formula

m=\frac{y_2-y_1}{x_2-x_1}

Where the points (x_1, y_1) and (x_2, y_2)  are two points belonging to the straight line

Notice in the graph that the line passes through the points

(0, 2) and (2, -1)

Then the slope is:

m=\frac{-1-2}{2-0}

m=\frac{-3}{2}

4 0
4 years ago
Help me with this thank you
alexgriva [62]
(-36x^4y+144x²y^6) / (-4x²y) = 
36xy*(x³+4xy^5) / (-4x²y) = 
-9*(x³+4xy^5) / x
7 0
3 years ago
Proving triangle similarities
sashaice [31]

did u ever get the answers

7 0
3 years ago
Help needed pleaseee
ohaa [14]

Answer:

A

Step-by-step explanation:

Since we're dealing with perpendicular lines, we take the recipricol of the m value of the original equation.

So the slope we're dealing with is 1/2.

And the equation we have so far is

y = 1/2x + b

Now we solve for b by plugging in the point (4,2).

2 = 1/2(4) + b

2 = 2 + b

b = 0

So the final equation is

y = 1/2x

8 0
3 years ago
Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7
rosijanka [135]
\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx

Notice that x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1). Decompose the integrand into partial fractions:

\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}
=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}

Integrating term-by-term, you get

\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx
=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C
5 0
4 years ago
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