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2 years ago

What are the zeros of f(x) = x2 - 8x + 16?

Mathematics

1 answer:

dolphi86 [110]2 years ago

8 0

x² - 8x + 16 = 0

(x - 4)^2 = 0

x = 4

Answer: One zero, x=4

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Simplify. 18x + 3xy + 5y −2(6xy − 2y + 4) A) 18x − 9xy + 9y − 8 B) 18x + 9xy + 9y − 8 C) 18x + 9xy − 9y + 8 D) 18x − 9xy + y − 8

Karolina [17]

18x+3xy+5y-2(6xy-2y+4)

18x+3xy+5y-12xy+4y-8

18x-9xy+9y-8

The answer is D

8 0

3 years ago

Read 2 more answers

Sally read that a recent survey found that 56% of all American adults own a smartphone. She asked her friend Alexandra what the

Crank

Answer:

This survey means that about 14 in every 25 adults in the survey had a smartphone.

Step-by-step explanation:

3 0

3 years ago

4b-4=3 b+3 What’s b=

julia-pushkina [17]

Answer:

b = 7

Step-by-step explanation:

4b - 4 = 3b + 3

4b - 3b = 3 + 4

b = 7

7 0

3 years ago

Read 2 more answers

Simplify the following algebraic expression: 2 (2x + 3y) + 3 (5 – 2x) +1+y

Gnoma [55]

Answer: -2x+7y+16

Step-by-step explanation:

1. Distribute 2 through the parentheses

4x+6y+3(5-2x)+1+y
4x+6y+15-6x+1+y

2. Collect like terms

-2x+6y+15+1+y
-2x+7y+15+1
-2x+7y+16

3. Solution, -2x+7y+16

5 0

3 years ago

Can someone help me in #66

VladimirAG [237]

$\bf log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y)
\\ \quad \\
% Logarithm of rationals
log_{{ a}}\left( \frac{x}{y}\right)\implies log_{{ a}}(x)-log_{{ a}}(y)
\\ \quad \\
% Logarithm of exponentials
log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)\\\\
-------------------------------\\\\
$

$\bf log_4\left( \cfrac{\sqrt{x^5y^7}}{zw^4} \right)\implies log_4(\sqrt{x^5y^7})-log_4(zw^4)
\\\\\\
log_4\left[(x^5y^7)^{^\frac{1}{2}}\right]-log_4(zw^4)\implies 
\cfrac{1}{2}log_4\left[(x^5y^7)\right]-log_4(zw^4)
\\\\\\
\cfrac{1}{2}\left[ log_4(x^5)+log_4(y^7) \right] -[log_4(z)+log_4(w^4)]
\\\\\\
\cfrac{1}{2}log_4(x^5)+\cfrac{1}{2}log_4(y^7)-[log_4(z)+log_4(w^4)]$

$\bf \cfrac{1}{2}\cdot 5log_4(x)+\cfrac{1}{2}\cdot 7log_4(y)-log_4(z)-4log_4(w)
\\\\\\
\cfrac{5}{2}log_4(x)+\cfrac{7}{2}log_4(y)-log_4(z)-4log_4(w)$

6 0

3 years ago