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Yanka [14]
4 years ago
7

will ran 4 miles on his first day of training the next day he ran 1/3 that distance how far did he run the second day

Mathematics
1 answer:
musickatia [10]4 years ago
4 0
He ran approximately 1 and 3/10th mile
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3 years ago
Tania is buying a guitar. Guitar Central has 20% off coupons available, and has the guitar Tania wants for $349. Music Mart has
Ksju [112]

Answer:

Music Mart offers a better deal, given that the price of the guitar is $ 219 compared to $ 279.20 for Guitar Central.

Step-by-step explanation:

Since Tania is buying a guitar, and Guitar Central has 20% off coupons available, and has the guitar Tania wants for $ 349, while Music Mart has the guitar Tania wants for $ 419, but is offering a $ 200 rebate, to determine which is the better deal the following calculations must be performed:

Guitar Central

100 - 20 = 80

349 x 0.8 = X

279.20 = X

Music mart

419 - 200 = X

219 = X

Therefore, Music Mart offers a better deal, given that the price of the guitar is $ 219 compared to $ 279.20 for Guitar Central.

7 0
3 years ago
Jordan jarred 18 liters of jam after 6 days. How many days does Jordan need to spend making jam if he wants to jar 27 liters of
tiny-mole [99]

Answer:

69420

Step-by-step explanation:

69 420 equils 69 420

8 0
4 years ago
At what x value does the function given below have a hole?<br><br> f(x)=x+3/x2−9
S_A_V [24]

Answer:

hole at x=-3

Step-by-step explanation:

The hole is the discontinuity that exists after the fraction reduces. (Still doesn't exist for original of course)

The discontinuities for this expression is when the bottom is 0. x^2-9=0 when x=3 or x=-3 since squaring either and then subtracting 9 would lead to 0.

So anyways we have (x+3)/(x^2-9)

= (x+3)/((x-3)(x+3))

Now this equals 1/(x-3) with a hole at x=-3 since the x+3 factor was "cancelled" from the denominator.

4 0
3 years ago
The equation V = 16300 (0.94)^t represents the value (in dollars) of a car t years after its purchase. Use this equation to comp
Dafna1 [17]

Solution:

Given:

V=16300(0.94)^t

The value of a car after t - years will depreciate.

Hence, the equation given represents the value after depreciation over t-years.

To get the rate, we compare the equation with the depreciation formula.

\begin{gathered} A=P(1-r)^t \\ \text{where;} \\ P\text{ is the original value} \\ r\text{ is the rate} \\ t\text{ is the time } \end{gathered}

Hence,

\begin{gathered} V=16300(0.94)^t \\ A=P(1-r)^t \\  \\ \text{Comparing both equations,} \\ P=16300 \\ 1-r=0.94 \\ 1-0.94=r \\ r=0.06 \\ To\text{ percentage,} \\ r=0.06\times100=6\text{ \%} \\  \\ \text{Hence, } \\ P\text{ is the purchase price} \\ r\text{ is the rate} \end{gathered}

Therefore, the value of this car is decreasing at a rate of 6%. The purchase price of the car was $16,300.

5 0
1 year ago
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