Answer:
p = -4, q = -3
Step-by-step explanation:
y = -2x +4 ... (1) perpendicular bisector of AB, slope = -2
slope of AB = 1/2
Line AB pass (8,3): (y-3) / (x-8) = 1/2
AB equation: y-3 = 1/2(x-8) y = 1/2x - 1 ... (2)
(2)-(1): 5/2 x = 5 x = 2
y = 0 (2,0) intercept of bisector and AB, it is midpoint of A (8,3) and (p,q)
(8+p)/2 = 2
<u>p = -4</u>
(3+q)/2 = 0
<u>q = -3</u>
Hi,
if it's 11:24, it wil be 12:13
✅(◠‿◕)
Hi,
1) ax²+2bx+c=0 have real roots then (2b)²-4ac>=0 ==> 4b²>=4ac ==> b²>=ac
2) bx²-2√(ac)x+b=0 have real roots then
(-2√(ac))²-4b²>=0==> 4ac>=4b²==> ac>=b²
So b²>=ac>=b²==> b²=ac
Answer:
81.6814
Step-by-step explanation:
Answer:
Answer is B and D.
Step-by-step explanation:
forgive me if I'm wrong!
I hope it's helpful!
