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vovikov84 [41]
3 years ago
15

Juan bought 5 cupcakes and 3 bearclaws for 45$. Lily bought 4 of the same cupcakes and 6 of the same bearclaws for 72$. What is

the price of each item?
Mathematics
1 answer:
puteri [66]3 years ago
8 0

Answer:

Cup cakes= $3

Bear claws = $10

Step-by-step explanation:

Let the orice of cupcakes be x and the price of bear claws be y

5x+ 3y= 45

4x + 6y= 72

Multiply equation 1 by 4 and equation 2 by 5

20x + 12y= 180

20x + 30y= 360

-18y= -180

y= 10

Substitute 10 for y in equation 1

5x + 3(10)= 45

5x + 30= 45

5x = 45-30

5x= 15

x= 15/5

= 3

Hence the price of cup cakes is 3 and bear claws is $10

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X represents the length of a deck. There are three parts to this equations. The 1. width, 2. the length, and 3. the 5 feet shorter. Using the key words, y = the width of a deck (uses the term is which means =) So that takes the width part out of the equation. Then, 5 feet shorter means -5 than a number. That takes away the 5 feet shorter part of the equation. That leaves x to equal the length of the deck.

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3 years ago
Assume the sample variances to be continuous measurements. Find the probability that a random sample of 25observations, from a n
konstantin123 [22]

Answer:

a) P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502

b)P(13.848Step-by-step explanation:

Previous concepts

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

For this case we assume that the sample variance is given by S^2 and we select a random sample of size n from a normal population with a population variance \sigma^2. And we define the following statistic:

T = \frac{(n-1) S^2}{\sigma^2}

And the distribution for this statistic is T \sim \chi^2_{n-1}

For this case we know that n =25 and \sigma^2 = 6 so then our statistic would be given by:

\chi^2 = \frac{(n-1)S^2}{\sigma^2}=\frac{24 S^2}{6}= 4S^2

With 25-1 =24 degrees of freedom.

Solution to the problem

Part a

For this case we want this probability:

P(S^2 > 9.1)

And we can multiply the inequality by 4 on both sides and we got:

P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502

And we can use the following excel code to find it: "=1-CHISQ.DIST(36.4,24,TRUE)"

Part b

For this case we want this probability:

P(3.462 < S^2

If we multiply the inequality by 4 on all the terms we got:

P(3.462*4 < 4S^2 < 4*10.745)= P(13.848< \chi^2And we can find this probability like this:P(13.848And we use the following code to find the answer in excel: "=CHISQ.DIST(42.98,24,TRUE)-CHISQ.DIST(13.848,24,TRUE)"

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2 years ago
Joelle's homework covers multiplication with powers of 1010 . The first question on her homework is 32.4\ \times10^232.4 ×10 2 .
grigory [225]

Answer:

103.424

Step-by-step explanation:

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3 years ago
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A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win
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Answer:

<u>The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,200 * 0.25 = 550 Megawatts

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Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

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Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

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oksian1 [2.3K]

Answer:

3.2

Step-by-step explanation:

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