<h3>~Geometry</h3>
Step-by-step explanation:
r³ = 125
r = 5 mm
...
V = 5³
V = 125 mm³
...
A = 6 . s²
A = 6 . 5²
A = 6 . 25
A = 150 mm²
#mathisfun
Using the z-distribution, we have that:
- For a 99% confidence level, a sample size of 127 is needed.
- For a 95% confidence level, a sample size of 74 is needed, meaning that a decrease in the confidence level decreases the needed sample size, as M and n are inverse proportional.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:
The margin of error is:
In which:
- is the sample mean.
- is the standard deviation for the population.
For a 99% confidence interval, , hence z is the value of Z that has a p-value of , so the critical value is z = 2.575.
The margin of error and population standard deviation are:
Hence we have to solve for n to find the needed sample size, as follows:
n = 126.4.
Rounding up, for a 99% confidence level, a sample size of 127 is needed.
For the 95% confidence interval, we have that z = 1.96, hence:
n = 73.3.
Rounding up, for a 95% confidence level, a sample size of 74 is needed, meaning that a decrease in the confidence level decreases the needed sample size, as M and n are inverse proportional.
More can be learned about the z-distribution at brainly.com/question/25890103
#SPJ1
Answer:
90 feet
Step-by-step explanation:
Because the infield of a baseball field is a square, the distance between each set of bases is equal.
P = 2l + 2w
360= 2(90) + 2w
360 = 180 + 2w
180 = 2w
90 = w
Answer:
8.20 am
Step-by-step explanation:
First, we have that Bus A will be back after 20 minutes, then after 40, then 60, 80, 100, 120, <u>140</u>, 160 minutes, etc.
Then, we have that Bus B will be back after 35 minutes, then 70, then 105, then <u>140</u>, 175....
From the list above we see that the first time they are both back at the station is after 140 minutes. (it's the MCM).
If we express this in terms of minutes, since one hour has 60 minutes, 2 hours have 120 minutes and thus, 140 minutes is 2 hours and 20 minutes.
Therefore, they will be both back at the station 2 hours and 20 minutes after they first departed at 6 am, so they will be back at the depot at 8.20 am