determine the range of the function in the table below. x f(x) 0 -4 2 2 4 8 {0, 2, 4} {-4, 2, 8} {(0, -4), (2, 2), (4, 8)} {(-4,
miv72 [106K]
<span>the range of the function in the table is the values under f(x). i.e. </span><span>{-4, 2, 8}</span>
58466
713*80 = 57040
713*2 = 1426
Answer:
The equation 'y = y + 1' represents NO SOLUTION.
Hence, option 'C' is true.
Step-by-step explanation:
a)
6a = 9a
subtract 9a from both sides
6a - 9a = 9a - 9a
-3a = 0
divide both sides by -3
-3a / -3 = 0/-3
Simplify
a = 0
b)
5x = 28
divide both sides by 5
5x/5 = 28/5
x = 28/5
c)
y = y + 1
subtract y from both sides
y - y = y+1-y
0 = 1
These sides are not equal, so
NO SOLUTION!
d)
y + 5 = 12
subtract 5 from both sides
y + 5 - 5 = 12 - 5
y = 7
Conclusion:
Therefore, the equation 'y = y + 1' represents NO SOLUTION.
Hence, option 'C' is true.
Collect the like terms
So 3n-n=2n and -1+4=3
(3n-1)+(4-n)=2n+3
Answer:
2(d-vt)=-at^2
a=2(d-vt)/t^2
at^2=2(d-vt)
Step-by-step explanation:
Arrange the equations in the correct sequence to rewrite the formula for displacement, d = vt—1/2at^2 to find a. In the formula, d is
displacement, v is final velocity, a is acceleration, and t is time.
Given the formula for calculating the displacement of a body as shown below;
d=vt - 1/2at^2
Where,
d = displacement
v = final velocity
a = acceleration
t = time
To make acceleration(a), the subject of the formula
Subtract vt from both sides of the equation
d=vt - 1/2at^2
d - vt=vt - vt - 1/2at^2
d - vt= -1/2at^2
2(d - vt) = -at^2
Divide both sides by t^2
2(d - vt) / t^2 = -at^2 / t^2
2(d - vt) / t^2 = -a
a= -2(d - vt) / t^2
a=2(vt - d) / t^2
2(vt-d)=at^2
