Polygon is Bounded by four lines. 3x+4=0 , 3x + 4 +25 =0, 4x-3y-25=0 , and 4x-3y+25=0,

Given the following formula, solve for h. <img src="https://tex.z-dn.net/?f=%20V%3D%20%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20r%5E%7

IgorC [24]

Multiply by the inverse of the coefficient of h.

$h=\dfrac{3V}{\pi r^2}$

3 0

3 years ago

Read 2 more answers

Approximately how many inches are in 6 meters? A) 72 inches B) 144 inches C) 216 inches D) 234 inches

Blababa [14]

The answer would be D

8 0

3 years ago

Resolve into partial fractions

lisabon 2012 [21]

Answer:

See below

Step-by-step explanation:

1)

$\frac{11 + x}{(2 - x)(x - 3)} = \frac{A}{2 - x} + \frac{B}{x - 3} \\ \\ \therefore \: \frac{11 + x}{(2 - x)(x - 3)} = \frac{A(x - 3) +B(2 - x) }{(2 - x)(x - 3)} \\ \\ \therefore \: 11 + x = Ax - 3A + 2B - Bx \\ \\ \therefore \: 11 + x = - 3A + 2B + Ax - Bx\\ \\ \therefore \: 11 + x = - 3A + 2B + (A - B)x \\ \\ equating \: the \: like \: terms \: on \: both \: sides \\ A - B = 1 \\ \therefore \: A = B + 1.....(1) \\ \\ - 3A + 2B = 11....(2) \\ from \: eq \: (1) \: and \: (2) \\ - 3(B + 1) + + 2B = 11 \\ \\ - 3B - 3 + 2B = 11 \\ \\ - B = 11 + 3 \\ \\ B = - 14 \\ A = - 14 + 1 = - 13 \\ \\ \frac{11 + x}{(2 - x)(x - 3)} = \frac{ - 13}{2 - x} + \frac{ - 14}{x - 3} \\ \\ \frac{11 + x}{(2 - x)(x - 3)} = - \frac{ 13}{2 - x} - \frac{ 14}{x - 3}$