Odd integers are 1 more than even ones even intergers are represetned as 2n where n is a whole number odd=2n+1 consecutive odd integers are 2 apart from each other so therefor the numbers are 2n+1,2n+1+2, 2n+1+2+2 or 2n+1, 2n+3, 2n+5 so they add up to 111 2n+1+2n+3+2n+5=111 add like terms 6n+9=111 subtract 9 from both sides 6n=102 divide both sides by 6 n=17 numbers are 2n+1,2n+3,2n+5 subsitute 2(17)+1=34+1=35 therefor since the other sare 2 more 35,37,39 are the numbers
are there 3 that equal 1111? solve and see if it is true 2n+1+2n+3+2n+5=1111 add like terms 6n+9=1111 subtract 9 from both sides 6n=1102 divide both sides by 6 n=183.666666666666 n is not whole so the answer is NO
