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JulsSmile [24]
3 years ago
9

Help fast please!!! Find the values of x and y.

Mathematics
2 answers:
Leno4ka [110]3 years ago
7 0

Answer:

Second option

x = 17√3; y = 34

Step-by-step explanation:

30 60 90 right triangle

Ratio of short leg : long leg : hypo = a :a√3 : 2a

Given short leg = 17

Long leg x = 17√3

Hypo. y = 2 * 17 = 34

Answer

x = 17√3; y = 34

frutty [35]3 years ago
5 0

Answer:

x = 17√3; y = 34

Step-by-step explanation:

30 60 90 right triangle

Ratio of short leg : long leg : hypo = a :a√3 : 2a

Given short leg = 17

Step-by-step explanation:

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krek1111 [17]

Answer:

Why do you talk with the other people so much???

Step-by-step explaWnation:

7 0
2 years ago
Hello, happy Friday, I am just here with some geometry questions.
irga5000 [103]

Answer:

VW = 43.2

Step-by-step explanation:

First, we can see that VZ = 88 - 55 = 33.

Then by the Triangle Proportionality Theorem, we can write that:

\displaystyle \frac{55}{33}=\frac{72}{VW}

Simplify:

\displaystyle \frac{5}{3}=\frac{72}{VW}

Cross-multiply:

216=5VW

So:

\displaystyle V=\frac{216}{5}=43.2

3 0
3 years ago
To find the sum of 4 and -5.
Katen [24]

Answer:

-1

Step-by-step explanation:

-5 + 4 = 1

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csf%20%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D%20%5Ccfrac%7B%5Csqrt%7Bx-1%7D-2x%20%7D%7Bx-7%7D" id=
BARSIC [14]
<h3>Answer:  -2</h3>

======================================================

Work Shown:

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}\left(\sqrt{x-1}-2x\right) }{ \frac{1}{x}\left(x-7\right) }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}*\sqrt{x-1}-\frac{1}{x}*2x }{ \frac{1}{x}*x-\frac{1}{x}*7 }\\\\\\

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}}*\sqrt{x-1}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}*(x-1)}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x}-\frac{1}{x^2}}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \frac{ \sqrt{0-0}-2 }{ 1-0 }\\\\\\\displaystyle L = \frac{-2}{1}\\\\\\\displaystyle L = -2\\\\\\

-------------------

Explanation:

In the second step, I multiplied top and bottom by 1/x. This divides every term by x. Doing this leaves us with various inner fractions that have the variable in the denominator. Those inner fractions approach 0 as x approaches infinity.

I'm using the rule that

\displaystyle \lim_{x\to\infty} \frac{1}{x^k} = 0\\\\\\

where k is some positive real number constant.

Using that rule will simplify the expression greatly to leave us with -2/1 or simply -2 as the answer.

In a sense, the leading terms of the numerator and denominator are -2x and x respectively. They are the largest terms for each, so to speak. As x gets larger, the influence that -2x and x have will greatly diminish the influence of the other terms.

This effectively means,

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 } = \lim_{x\to\infty} \frac{ -2x }{ x} = -2\\\\\\

I recommend making a table of values to see what's going on. Or you can graph the given function to see that it slowly approaches y = -2. Keep in mind that it won't actually reach y = -2 itself.

5 0
3 years ago
Which could be the measure of <br> A.) 38<br> B.) 42<br> C.) 44<br> D.) 52
vichka [17]
Well you can check what type of angle it is! like depending on how it is slouched like a right angle is 90° for example.
3 0
3 years ago
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