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Gekata [30.6K]
4 years ago
5

Please someone help solve for x:

Mathematics
2 answers:
Harrizon [31]4 years ago
5 0
X=1
5*5*5=25*5=125
5 to the 3rd power is equal to 125

Nikolay [14]4 years ago
4 0
The answer is 1 because we cube the 5x and you will get 125, and then you divide 125x by 125 and you get = 1
HOPE THIS HELPS!!!!
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Consider the following two loans for P=$12,000.
n200080 [17]

Answer:

Simple interest-?

Step-by-step explanation:

P= 12000

T=5yrs

R=5%

Now,

Simple interest - PTR/100

= 12000*5*5/100

= $3000

Again,

P=12000

T=3yrs

R=8%

Now,

Simple interest - PTR/100

= 12000*3*8/100

= $2880

Hope this helps.

4 0
2 years ago
The average value of y=v(x) equals 4 for 1≤x≤6, and equals 5 for 6≤x≤8. what is the average value of v(x) for 1≤x≤8 ?
Tomtit [17]
The average value over the interval is the area under the curve divided by the width of the interval.

Area = 4*(6 -1) +5(8 -6) = 30
Width = 8 - 1 = 7

Average value = 30/7 = 4 2/7

7 0
3 years ago
What is the radius and center of the circle given by the equation (x-5)^{2}+(y+2)^{2} = 81/4
artcher [175]

Answer:

The center is (5, -2) and the radius is 9/2

Step-by-step explanation:

The equation of a circle can be written by

(x-h) ^2 + (y-k)^2 = r^2

where (h,k) is the center and r is the radius

(x-5)^{2}+(y+2)^{2} = 81/4

( (x-5)^{2}+(y- -2)^{2} = (9/2)^2

The center is (5, -2) and the radius is 9/2

6 0
3 years ago
Help I need an answer as soon as possible
SSSSS [86.1K]

Answer:

charlie is the one,im pretty sure

3 0
3 years ago
Erik and Caleb were trying to solve the equation: 0=(3x+2)(x-4) Erik said, "The right-hand side is factored, so I'll use the zer
Mumz [18]

Answer:

C) Both

Step-by-step explanation:

The given equation is:

0=(3x+2)(x-4)

To solve the given equation, we can use the Zero Product Property according to which if the product <em>A.B = 0</em>, then either A = 0 OR B = 0.

Using this property:

(3x+2) = 0 \Rightarrow \bold{x = -\frac{2}{3}}\\(x-4) = 0 \Rightarrow \bold{x = 4}

So, Erik's solution strategy would work.

Now, let us discuss about Caleb's solution strategy:

Multiply (3x+2)(x-4) i.e. 3x^2-12x+2x-8 = 3x^2-10x-8

So, the equation becomes:

0=3x^2-10x-8

Comparing this equation to standard quadratic equation:

ax^2+bx+c=0

a = 3, b = -10, c = -8

So, this can be solved using the quadratic formula.

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\dfrac{-(-10)\pm\sqrt{(-10)^2-4\times3 \times (-8)}}{2\times 3}\\x=\dfrac{-(-10)\pm\sqrt{196}}{6}\\x=\dfrac{10\pm14}{6} \\\Rightarrow x= 4, -\dfrac{2}{3}

The answer is same from both the approaches.

So, the correct answer is:

C) Both

3 0
3 years ago
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