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valentina_108 [34]
4 years ago
7

Which diagram shows the most useful positioning of a rectangle in the first quadrant of a coordinate plane? Answers are in the p

ictures.

Mathematics
2 answers:
Verdich [7]4 years ago
6 0
Use this one and that will be useful

me thinks you do not have to deal with all the other stuff. you jus tuse "a" for the height and "b" with the width

taurus [48]4 years ago
5 0

Answer:

Figure C having points (1,1), (b,1), (b,a) and (1,a) will be the most useful.

Step-by-step explanation:

We are required to position a rectangle in the first quadrant in the most useful way possible.

As we can see that,

In figure A, the line joining (1,0) and (b,0) lies on the x-axis.

In figure B, the points (0,a) and (a,0) lies on the x-axis.

In figure D, the line joining (0,0) with (b,0) and (0,0) with (0,a) lies on the x-axis.

But, we need the figure to be placed inside the Ist quadrant.

So, all above options are discarded.

Hence, option C is correct.

You might be interested in
student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te
alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = \frac{1}{4}.

Thus, the probability that the student does not receive version A = 1-\frac{1}{4} = \frac{3}{4}.

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}

= (\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5

= (\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]

= (\frac{3}{4^4})[1+\frac{1}{16}]

= (\frac{3}{256})[\frac{17}{16}]

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0
3 years ago
What is twenty-three thousandths written in standard form
denpristay [2]

Answer: 0.023 is twenty-three thousandths written in standard form!

5 0
3 years ago
Read 2 more answers
Chang is 6 inches taller than nancy. Use n for nancy’s height in inches. Write an expression to represent chang's height. Then e
Irina-Kira [14]

Answer:

Expression Chang:

N+6

If N = 60

Then 60+6=66

Chang is 66 inches

Step-by-step explanation:

3 0
3 years ago
Can u pls answer this for me <br><br><br> 8+.0573+1.64=
Wittaler [7]
9.6973 will be your answer
5 0
3 years ago
Write an equation of the line that passes through (5, −1) and is perpendicular to the line y=12x−1.
Lisa [10]

Step-by-step explanation:

solution

let,A(5,-1)

given

y=12x-1

or, y = 12 × x + (-1)

comparing it with y=mx+c

we get

x=1

y = c = -1

now

A(5,-1) and B(1,-1)

equation of line is,

(y-y1)/(x-x1) = (y2-y1)/(x2-x1)

or, (y+1)/(x-5) = (-1+1)/(1-5)

or, (y+1)/(x-5) = 0/-4

cross multiply

-4y-4 = 0

or, 0=4y+4

or, 4y+4=0 is the required eqn

I think this is the process and answer too.

I hope this helps you

4 0
3 years ago
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