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ioda
3 years ago
13

Your weight on different planets is affected by gravity. An object that weighs 150 pounds on earth Weighs only 56.55 pounds on m

ars. The same object wheighs only 24.9 what percent of an objects Earth Weight is its weight on mars and on the moon
Mathematics
1 answer:
slavikrds [6]3 years ago
4 0
<span>According to a map, the distance between Hilltop and Valleyfloor is 1 3/4 inches. If the map uses a scale of ¼ inch to represent 1 mile, what is the actual distance in miles from Hilltop to Valleyfloor?</span>
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to practice for an Ironman competition John swim 0.86 kilometers each day for three weeks how many meters did he swim in those 3
NARA [144]
1 kilometers =1000 meters
0.86km=0.86*1000=860m
John swam 860 meters each day.
1 week = 7 days
3weeks=3*7=21
21*860=18060 m
Therefore he swam 18060 meters in those three weeks.
6 0
3 years ago
Read 2 more answers
−2t−5&lt;9<br><br> Hiiiiiiii<br><br> Huuuu
Brilliant_brown [7]

Answer:

t > -7

Step-by-step explanation:

To solve for t, first add 5 to both sides:

-2t - 5 < 9

-2t < 14

Divide each side by -2, and flip the inequality because we are dividing by a negative number:

-2t < 14

t > -7

So, the solution is t > -7

4 0
3 years ago
Read 2 more answers
Does anyone know what 8x1/6 is?
mario62 [17]
Answer: 1.333333333333333333334
5 0
3 years ago
Read 2 more answers
Imagine a recessive mutation in rabbits that causes wiry fur (whereas the dominant, normal allele causes fluffy fur). If two het
arsen [322]

Answer: the required probability is  0.03516

Step-by-step explanation:

Given the data in the question;

let F represent dominant allele that causes fluffy fur and

f represent corresponding recessive allele that causes wiry fur

here are the possible genotypes and corresponding phenotypes;

FF = Fluffy fur

Ff = Fluffy fur

ff = Wiry fur

genotype of parents is Ff and Ff

and there cross will be; Ff x Ff

now Offspring will be;

                                   F                      f

F                                FF                    Ff

f                                 Ff                     ff

so the probability that the offspring will have fluffy fur = 3/4

and the probability that the offspring will have wiry fur = 1/4

The probability that the first 2 out of 4 offspring will have fluffy fur will be;

⇒ 3/4 × 3/4 × 1/4 × 1/4 =  0.03516

 Therefore, the required probability is  0.03516

6 0
3 years ago
PRECAL:<br> Having trouble on this review, need some help.
ra1l [238]

1. As you can tell from the function definition and plot, there's a discontinuity at x = -2. But in the limit from either side of x = -2, f(x) is approaching the value at the empty circle:

\displaystyle \lim_{x\to-2}f(x) = \lim_{x\to-2}(x-2) = -2-2 = \boxed{-4}

Basically, since x is approaching -2, we are talking about values of x such x ≠ 2. Then we can compute the limit by taking the expression from the definition of f(x) using that x ≠ 2.

2. f(x) is continuous at x = -1, so the limit can be computed directly again:

\displaystyle \lim_{x\to-1} f(x) = \lim_{x\to-1}(x-2) = -1-2=\boxed{-3}

3. Using the same reasoning as in (1), the limit would be the value of f(x) at the empty circle in the graph. So

\displaystyle \lim_{x\to-2}f(x) = \boxed{-1}

4. Your answer is correct; the limit doesn't exist because there is a jump discontinuity. f(x) approaches two different values depending on which direction x is approaching 2.

5. It's a bit difficult to see, but it looks like x is approaching 2 from above/from the right, in which case

\displaystyle \lim_{x\to2^+}f(x) = \boxed{0}

When x approaches 2 from above, we assume x > 2. And according to the plot, we have f(x) = 0 whenever x > 2.

6. It should be rather clear from the plot that

\displaystyle \lim_{x\to0}f(x) = \lim_{x\to0}(\sin(x)+3) = \sin(0) + 3 = \boxed{3}

because sin(x) + 3 is continuous at x = 0. On the other hand, the limit at infinity doesn't exist because sin(x) oscillates between -1 and 1 forever, never landing on a single finite value.

For 7-8, divide through each term by the largest power of x in the expression:

7. Divide through by x². Every remaining rational term will converge to 0.

\displaystyle \lim_{x\to\infty}\frac{x^2+x-12}{2x^2-5x-3} = \lim_{x\to\infty}\frac{1+\frac1x-\frac{12}{x^2}}{2-\frac5x-\frac3{x^2}}=\boxed{\frac12}

8. Divide through by x² again:

\displaystyle \lim_{x\to-\infty}\frac{x+3}{x^2+x-12} = \lim_{x\to-\infty}\frac{\frac1x+\frac3{x^2}}{1+\frac1x-\frac{12}{x^2}} = \frac01 = \boxed{0}

9. Factorize the numerator and denominator. Then bearing in mind that "x is approaching 6" means x ≠ 6, we can cancel a factor of x - 6:

\displaystyle \lim_{x\to6}\frac{2x^2-12x}{x^2-4x-12}=\lim_{x\to6}\frac{2x(x-6)}{(x+2)(x-6)} = \lim_{x\to6}\frac{2x}{x+2} = \frac{2\times6}{6+2}=\boxed{\frac32}

10. Factorize the numerator and simplify:

\dfrac{-2x^2+2}{x+1} = -2 \times \dfrac{x^2-1}{x+1} = -2 \times \dfrac{(x+1)(x-1)}{x+1} = -2(x-1) = -2x+2

where the last equality holds because x is approaching +∞, so we can assume x ≠ -1. Then the limit is

\displaystyle \lim_{x\to\infty} \frac{-2x^2+2}{x+1} = \lim_{x\to\infty} (-2x+2) = \boxed{-\infty}

6 0
2 years ago
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