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Sveta_85 [38]
2 years ago
11

show that the the product of the first two numbers 28,48 of that stem is equal to the product of their LCM and HCF

Mathematics
1 answer:
Oliga [24]2 years ago
5 0

Answer:

HCF is 4

LCM is 336

Step-by-step explanation:

2/28 , 48

2/14 , 24

2/7 , 12

2/7 , 6

3/7 , 3

7/7 , 1

1 , 1

HCF is 2 × 2 =4

LCM is 2 × 2 × 2 × 2 × 3 × 7 = 336

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5 x 3 = 15
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15 + 0.9 = 15.9

Hope this helps! :)
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6 0
2 years ago
Rationalize the denominator of square root of negative 9 over open parentheses 4 minus 7 i close parentheses minus open parenthe
AlekseyPX
The answer is
\frac{-6i-3}{5}.

Before we rationalize the denominator, we must simplify the numerator and denominator.  We evaluate the square root on the top, and combine like terms on the bottom:
\frac{\sqrt{-9}}{(4-7i)-(6-6i)}
\\
\\=\frac{\sqrt{9i^2}}{4-6-7i--6i}
\\
\\=\frac{3i}{-2-i}

To rationalize the denominator, we multiply by the conjugate.  The conjugate is found by making the imaginary term of the complex number, the i part, the opposite sign.  The conjugate of -2-i is -2+i:

\frac{3i}{-2-i}\times \frac{-2+i}{-2+i}
\\
\\=\frac{3i(-2+i)}{(-2-i)(-2+i)}
\\
\\=\frac{3i\times -2 + 3i\times i}{-2\times -2 + -2\times i + -2\times -i + -i\times i}
\\
\\=\frac{-6i+3i^2}{4-2i+2i-i^2}
\\
\\=\frac{-6i+3(-1)}{4-i^2}=\frac{-6i-3}{4-(-1)}=\frac{-6i-3}{5}
7 0
3 years ago
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