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Sveta_85 [38]
3 years ago
11

show that the the product of the first two numbers 28,48 of that stem is equal to the product of their LCM and HCF

Mathematics
1 answer:
Oliga [24]3 years ago
5 0

Answer:

HCF is 4

LCM is 336

Step-by-step explanation:

2/28 , 48

2/14 , 24

2/7 , 12

2/7 , 6

3/7 , 3

7/7 , 1

1 , 1

HCF is 2 × 2 =4

LCM is 2 × 2 × 2 × 2 × 3 × 7 = 336

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I want to say A because 168 tenths should equal 168 thousandths
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3 years ago
Need to rewrite b^4(2b^2+b)
Yuri [45]
Are you trying to distribute the b^4 or factor it?

b^4 [(2b^2) + b]

Distributed:
[2(b^6) + (b^5)]

Factored:
b^5 [2b + 1]

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3 years ago
There is a bag of tiles where 8 are red, 5 are blue, 4 are orange, and 3 are green. If one is picked at random, replaced, and an
sesenic [268]

Answer:

i think it is 1/100

Step-by-step explanation:

4/20^2 add all the marbles number together than put the amount of orange marbles on top of it so it is 4/20 than square it

8 0
2 years ago
F(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-%5Csqrt%7Bx%5E2%2B2x-15%7D" id="TexFormula1" title="\sqrt{x+7} -\
elena-s [515]

Answer:

x >= -7  ................(1a)

x >= 3   ...............(2a1)

Step-by-step explanation:

f(x) =  \sqrt{x+7}-\sqrt{x^2+2x-15}  .............(0)

find the domain.

To find the (real) domain, we need to ensure that each term remains a real number.

which means the following conditions must be met

x+7 >= 0  .....................(1)

AND

x^2+2x-15 >= 0 ..........(2)

To satisfy (1),  x >= -7  .....................(1a) by transposition of (1)

To satisfy (2), we need first to find the roots of (2)

factor (2)

(x+5)(x-3) >= 0

This implis

(x+5) >= 0 AND (x-3) >= 0.....................(2a)

OR

(x+5) <= 0 AND (x-3) <= 0 ...................(2b)

(2a) is satisfied with x >= 3   ...............(2a1)

(2b) is satisfied with x <= -5 ................(2b1)

Combine the conditions (1a), (2a1), and (2b1),

x >= -7  ................(1a)

AND

(

x >= 3   ...............(2a1)

OR

x <= -5 ................(2b1)

)

which expands to

(1a) and (2a1)   OR  (1a) and (2b1)

( x >= -7 and x >= 3 )  OR ( x >= -7 and x <= -5 )

Simplifying, we have

x >= 3  OR ( -7 <= x <= -5 )

Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.

3 0
3 years ago
Read 2 more answers
HELP HELP ME PLZ !!!
nikklg [1K]

Answer:

GK=JK

Step-by-step explanation:

SSS congruency  is side-side-side congruency. We are given that GH=JH and KH=KH, which are both sides.

For SSS, we need 3 pairs of congruent sides. We already have 2 pairs.

The options are:

<G=<J

<H=<H

GK=JK

the first two options, <G=<J and <H=<H are talking about congruent angles. We don't need to know about congruent angles for SSS

GK=JK is talking about a pair of congurent sides. Then, we would have 3 pairs of congruent sides, satisfying the criteria needed for SSS. Therefore, we must know that GK=JK.

Hope this helps!

3 0
3 years ago
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