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kari74 [83]
2 years ago
10

What is the horizontal asymptote of j (x) = StartFraction 14 x cubed + 45 Over 2 x cubed + x + 9 EndFraction

Mathematics
1 answer:
melomori [17]2 years ago
4 0

Answer:

It's C! y = 7

Step-by-step explanation:

Plugged the equation into an online calculator and got that answer :) Have a good day!

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Which statement is true about ∠1 and ∠2?
gavmur [86]

Answer: Most likely A

Step-by-step explanation:

the reason I say its A is because of the face that congruent means in line not and straight. Though in your answer it shows that they are not alined so that leaves us with complemantary and the 2 complementary answer choices are

A & C but C is wrong because it say alternate which also means the that they would be 2 different angels so yeah I'm gonna go for A.

Good luck :)

5 0
2 years ago
Sarah has $18.00 and she earns $7.25 an hour at work. what’s the equations
BigorU [14]

Answer:

y = 7.25x + 18

Step-by-step explanation:

18 is the base. so it goes last.

7.25 is the amount being raised per a certain amount (hours) so its 7.25x

6 0
3 years ago
Can someone help me with this! It would be much appreciated!!
love history [14]

Answer:

1. parallelogram

2. trapezoid

3.rectangle

4. parallelogram

5. trapezoid

6. rhombus

7.rectangle

8. rhombus

3 0
3 years ago
I need help with 12 and 13 please.
Cerrena [4.2K]
Just add up all the angles hope you get it right
7 0
3 years ago
Using the quadratic formula to solve 4x2 – 3x + 9 = 2x + 1, what are the values of x?
yaroslaw [1]

Answer:

The value of x is:

x=\dfrac{5\pm \sqrt{103}i}{8}

Step-by-step explanation:

we have to use the quadratic formula to solve for x.

The equation is given as:

4x^2-3x+9=2x+1

which could also be written as:

4x^2-3x+9-2x-1=0\\\\4x^2-3x-2x+9-1=0\\\\\\4x^2-5x+8=0

The quadratic formula for the quadratic equation of the type:

ax^2+bx+c=0 is given as:

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Here we have:

a=4, b=-5 and c=8.

Hence, by the quadratic formula we have:

x=\dfrac{-(-5)\pm \sqrt{(-5)^2-4\times 8\times 4}}{2\times 4}\\\\x=\dfrac{5\pm \sqrt{25-128}}{8}\\\\\\x=\dfrac{5\pm \sqrt{103}i}{8}

Hence, the value of x is:

x=\dfrac{5\pm \sqrt{103}i}{8}

8 0
3 years ago
Read 2 more answers
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