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VashaNatasha [74]
3 years ago
15

In a box of crayons, 24% of the crayons are blue.There are 48 blue crayons in the box.

Mathematics
1 answer:
-BARSIC- [3]3 years ago
5 0
D. There are 200 crayons in the box. If you just made it 25% of 200 is 50 which is the closest number to answer based on a quick estimation:) 
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This is ridiculous help help
77julia77 [94]
130.
Since angle 1 and 5 equal 100 each angle is 50. Since 1 and 3 are supplementary subtract 180 and 50
4 0
3 years ago
Find the average temperature on that part of the plane 2x + 5y +z = 9 over the square |x| <= 1, y <= 1, where the temperat
vivado [14]

Answer:

This question answer is attached in the attachment,

Step-by-step explanation:

5 0
3 years ago
PLEASE. HELP.
jekas [21]
I think the answer is A I’m not sure tho
6 0
3 years ago
In a random sample of n1 = 162 males, there are x1 = 63 people that have blue eyes. In a random sample of n2 = 333 females, ther
sesenic [268]

Answer:

z = 2.1784 > 1.96,

Reject the null hypothesis

Step-by-step explanation:

For the males:

n1  = 162, x1 = 63

P1 = x 1/ n1 = 0.3889

For the Females:

n2 = 333,

x2 = 97

P 2 = x2/n2

= 0.2913

P 1= P2 Null hypothesis

P 1 is not equal to P 2 alternative hypothesis

Pooled proportion:

P= (x1 + x2) /( n1+ n2)

= (63 + 97) / (162 + 333)= 0.3232

Test statistics :

Z= (p1 - p2) /√p(1-p)× (1/n1 + 1/n2)

0.3889- 0.2913 / √0.3232 × 0.6768 × (1/162 +1/333)

=2.1784

c) Critical value :

Two tailed critical value, z critical = Norm.S .INV (0.05/2) = 1.960

Reject H o if z < -1.96 or if z > 1.96

d) Decision:

z = 2.1784 > 1.96,

Reject the null hypothesis

7 0
3 years ago
The managers of an airline analyzed a random sample of flights and found that 48 out of 50 were on time. The airline has 450 fli
Elena L [17]

Answer:

432 flights are expected to arrive at time.

Step-by-step explanation:

48/50= 0.96

0.96 x 450=  432

8 0
3 years ago
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