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GarryVolchara [31]
3 years ago
7

A national magazine stated that atâ most, 16% of millennials have a sports club membership. Formulate an appropriateâ one-sample

test of hypothesis to test this.
Determine the nullâ hypothesis, H0â, and the alternativeâhypothesis, H1.
Mathematics
1 answer:
Norma-Jean [14]3 years ago
7 0

Answer:

H_0: p\leq0.16

H_1: p>0.16

Step-by-step explanation:

Let p be the population proportion of millennials have a sports club membership.

Given : A national magazine stated that at-most, 16% of millennials have a sports club membership.

That means p ≤ 0.16 .  (less than or equal to 0.16 or 16%)

Since the null hypothesis contains equality sign  , so the null hypothesis for this objective will be : H_0: p\leq0.16

Also, The alternative hypothesis is just the opposite statement of the null hypothesis , so our alternative hypothesis becomes : H_1: p>0.16

Hence, the null hypothesis and alternative hypothesis are :

H_0: p\leq0.16

H_1: p>0.16

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Should politics discuss whether women can get abortion??? Why or why not????
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Step-by-step explanation:

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8 0
3 years ago
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A record club has found that the marginal​ profit,
tankabanditka [31]

Solution :

Given :

$P'(x) = -0.0008x^3+0.20x^2+46.8x,$    for x ≤ 200

Total profit when 120 members are enrolled is :

$\sum_{i=1}^6P'(x_i) \Delta x$      with \Delta x = 20

Using the left end points, we get,

The values of x_i are : { 0, 20, 40, 60, 80, 100}

Therefore,

$P'(x_1) = P'(0)=-(0.0008)(0)^3+(0.20)(0)^2+(46.8)(0)$

                        = 0

$P'(x_2) = P'(20)=-(0.0008)(20)^3+(0.20)(20)^2+(46.8)(20)$

                          = 1009.6

$P'(x_3) = P'(40)=-(0.0008)(40)^3+(0.20)(40)^2+(46.8)(40)$

                         =  2140.8

$P'(x_4) = P'(60)=-(0.0008)(60)^3+(0.20)(60)^2+(46.8)(60)$

                         = 3355.2

$P'(x_5) = P'(80)=-(0.0008)(80)^3+(0.20)(80)^2+(46.8)(80)$

                         = 4614.4

$P'(x_6) = P'(100)=-(0.0008)(100)^3+(0.20)(100)^2+(46.8)(100)$

                           = 5880

$\sum_{i=1}^6P'(x_i) \Delta x = P'(x_1)\Delta x + P'(x_2)\Delta x + P'(x_3)\Delta x + P'(x_4)\Delta x + P'(x_5)\Delta x + P'(x_6)\Delta x $  

= (0)(20) + (1009.6)(20) + (2140.8)(20) + (3355.2)(20) + (4614.4)(20) + (5880)(20)

= (20)( 0 + 1009.6 + 2140.8 + 3355.2 + 4614.4 + 5880)

= (20)(17,000)

= 340,000 cents

$=\frac{340000}{100} \ \text{dollars}$

= 3400 dollars

Hence, the required total profit is 3400 dollars.

8 0
3 years ago
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Fittoniya [83]

Answer:

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Step-by-step explanation:

Let x be the percentage then...

x\%(4)=2

Start by dividing both sides by 4:

x\%=\frac{2}{4}

Simplify the fraction:

x\%=\frac{1}{2}

Then, multiply the fraction by 50/50, so we can get a number over 100 (that number would be the percentage). Note we can only multiply it by 50/50 since it is essentially multiplying the fraction by 1.

x\%=\frac{1}{2}*\frac{50}{50}\\x\%=\frac{50}{100}\\x=50\%

4 0
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 A.) 68,000 
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