Question

Please can anyone help answer this question? It would be greatly appreciated!!! :)

Answer 1

Answer:

0.667

Step-by-step explanation:

Angle in a circle = 360°

Area of total shaded parts = 60 + 60 = 120°

Area of total unshaded parts = 360-120 = 240°

Probability that a random selected point within the circle falls in the unshaded area

= 240/360

= 2/3

≈ 0.667

I apologize in advance if I made a mistake.

Answer 2

Answer:

The probability that point falls in the white area is 2/3 or 0.667

Step-by-step explanation:

Consider the provided figure.

As we know there are 360 degrees in a circle.

The diameter divides the circle in two equal half 180° each.

The angle measure of white part in upper half is 180°-60°-60°=60°

The total angle measure of white part in the provided figure is: 180°+60°=240°

Now we need to find the probability that a random selected point falls in the white area

$Probability=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$

Substitute Number of favorable outcomes=240° and Total number of outcomes = 360° in the above formula.

$Probability=\frac{240}{360}$

$Probability=\frac{2}{3}\ \text{or}\ 0.667$

Hence, the probability that point falls in the white area is 2/3 or 0.667