Two trains travel a 160 km track each day. The express travels 10 km h^-1 faster and take 30 minutes less time than the normal t
rain. Find the speed of the express.
1 answer:
Let s = the speed of the slower train in km/hrs+10 = the speed of the faster train in km/hrLet t = time in hrs for the slower train to go 160 kmt-5 = time in hrs for faster train to go 160 km---------------Slower train:(1)
160=s.t
Faster train:(2) 160=(s+10) .(t-.5)From (1)(1) t=160/s
use the relations given in following screenshot and then use quadratic equation.
160=s.t
Faster train:(2) 160=(s+10) .(t-.5)From (1)(1) t=160/s
use the relations given in following screenshot and then use quadratic equation.
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Answer:
Option (4)
Step-by-step explanation:
From the graph attached,
A dotted line passes through two points (3, 1) and (-3, -3)
Let the equation of the given line is,
y = mx + b
where 'm' = slope of the line
b = y-intercept
Slope of a line passing through and
is,
m =
For the given points,
m =
m =
y-intercept 'b' = -1
Therefore, equation of the given line will be,
Since graphed line is a dotted line so it's representing an inequality(having < or > sign)
And the shaded part is below the dotted line,
Inequality will be,
y <
Therefore, Option (4) will be the answer.