Two trains travel a 160 km track each day. The express travels 10 km h^-1 faster and take 30 minutes less time than the normal t
rain. Find the speed of the express.
1 answer:
Let s = the speed of the slower train in km/hrs+10 = the speed of the faster train in km/hrLet t = time in hrs for the slower train to go 160 kmt-5 = time in hrs for faster train to go 160 km---------------Slower train:(1)
160=s.t
Faster train:(2) 160=(s+10) .(t-.5)From (1)(1) t=160/s
use the relations given in following screenshot and then use quadratic equation.
160=s.t
Faster train:(2) 160=(s+10) .(t-.5)From (1)(1) t=160/s
use the relations given in following screenshot and then use quadratic equation.
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Use distributive property:
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Combine Like Terms:
Therefore, the answer to your question is -4x² + 3x + 4. Hope this helps and have a fantastic day!
Answer:
125 traffic cones
Step-by-step explanation:
In order to find the total number of meters, we can set up a proportion to find based on the ration of cm to m:
, where 'x' is the number of meters
cross-multiply: x = 25(50) or x = 1250 m
Since there is a cone every 10 m, we can divide the total number of meters by 10:
1250/10 = 125 cones