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frosja888 [35]
4 years ago
5

Probability 1/43/41/25/8??​

Mathematics
1 answer:
Sindrei [870]4 years ago
4 0

Answer:

1/2

Step-by-step explanation:

There are exactly 6 shaded regions; for every shaded region, there is also an unshaded region -- making this value 6 as well.

There are 12 possible outcomes, and 6 events

To determine probability, we divide the number of events by the number of possible outcomes, like this:

6/12=1/2\\1/2=.50\\

.50 = 50% or 1/2 chance.

#SpreadTheLove

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given

S = \{1,2,3,4, 5,6,7,8, 9, 10, 11, 12\}

E = \{1,2, 3, 4, 5, 6,7\}

F =\{1,5,6, 7, 8,9\}

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H = \{2, 3, 4\}

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Sets of E and F = E n F

E\ n\ F = \{1,2, 3, 4, 5, 6,7\}\ n\ \{1,5,6, 7, 8,9\}

List out common elements

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Sets of F and G = F n G

F\ n\ G =\{1,5,6, 7, 8,9\}\ n\ \{9,10, 11, 12\}

List out common elements

F\ n\ G =\{9\}

<em>They are not mutually exclusive because </em>n(F\ n\ G) \neq 0<em />

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Sets of F or G = F U G

F\ U\ G =\{1,5,6, 7, 8,9\}\ U\ \{9,10, 11, 12\}

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F\ U\ G =\{1,5,6, 7, 8,9,10, 11, 12\}

Solving P(F U G)

P(F\ U\ G) = \frac{n(F\ U\ G)}{n(S)}

n(F\ U\ G) = 9

n(S) = 12

Hence;

P(F\ U\ G) = \frac{9}{12}

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P(F\ U\ G) = \frac{3}{4}

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