Answer: No, the normal curve cannot be used.
Step-by-step explanation:
The theorem of the Normal approximation states that if X is B(n,p) then for large n X is N(np, np(1-p)).
The accuracy of this approximation is good
i. for n > [10/p(1-p)]
ii. p is close to 1/2
Hence given p= 4% = 0.04,
q = 1 - 0.04 = 0.96
Let N = [10/p(1-p)]
We find N = 10/p(1-p) = 10/(0.04× 0.96)
N ~= 260
Since n < 260 and p < 0.5
The approximation is not a good one
Hi what are you trying to do here?
Find a common multiplier between both which would be 4. then divide each term by 4. all you have left stays in the parenthesees.
4 (2x+5)
Answer:
k = -3
Step-by-step explanation:
log7(-5k - 3) = log7 (-4k)
---> -5k - 3 = -4k
-k - 3 = 0
k = -3
Answer:
((2^(-2))÷(3^3))^4=
Step-by-step explanation: expand
