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yKpoI14uk [10]
3 years ago
7

Why is a wheelbarrow and example of a 2nd class lever

Mathematics
1 answer:
kodGreya [7K]3 years ago
3 0
Hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
You might be interested in
Jose is at school from 7:30 a.m. to 2:30 p.m. every day. How many minutes is he at school?
Ksivusya [100]

Answer:

420 minutes

Step-by-step explanation:

7:30am to 2:30pm

=7:30to 14:30

=14.30-7.30=

7hours

in minutes;

7×60

= 420minutes

like and Mark as brainliest

5 0
3 years ago
If the mean of a normal distribution is 210, what is the median of the
AleksandrR [38]

Answer:

210

Step-by-step explanation:

In a normal distribtuion mean=mode=median

so 210=median

3 0
3 years ago
Two consecutive even integers have the following property. When the smaller integer is added to three times the larger integer,
polet [3.4K]
 let x be the first integer
 x+ 2 the second integer  ( two consecutive even ) 

smaller integer  added to three times the larger  <span>x + 3 ( x+2)
  </span>two less than five times the smaller  <span>5x - 2</span>

x + 3 ( x+2)   =  5x - 2

x+3x +6 = 5x -2 

x=8       
the first  integer = 8
the second is  x+2 =10 



4 0
3 years ago
I need help with this question. Question is in image below. ​
ExtremeBDS [4]

Answer:

A. Answer is 2263.

Checkpoint 1 is -86 Checkpoint 4 is 2177

Subtract -86 from 2177....2177-(-86)   

=2263

2263 is how much higher checkpoint 1 (-86) is from checkpoint 4 (2177)

B. 239 FEET.

the altitude of the hill must be subtracted by the depth of the ckeckpoint(2)(-189)

therefore the altitude of the hill comes out to be 428-189=239feet.

therefore,the actual altitude of the hill is 239 feet.

7 0
2 years ago
What will be angle COD If: angle COD minus angle KOD equals 61degrees and angle COD minus angle KOC equals 53degrees?
kenny6666 [7]

Use algebra for such problems
let, Angle COD = x
Angle KOD = y
Angle KPC = z
Given ,. x - y = 61° ( Equation 1 )
x - z = 53° ( Equation 2 )
Subtract 1st equation from 2nd and you'll get :

z - y = 8° ( Equation 3 )
Now since , x + y + z = 180° ( Equation 4 )
Add Equation 3 to Equation 4 and you'll get
x + 2z = 188° ( Equation 5)
From Equation 2 we know that , x -z = 53°
or, x = 53° + z ( Equation 6 )
Put this value of 'x' in Equation 5 and solve for z. you'll get :
(53° + z) + 2z = 188°
or
3z = 188 - 53 = 135°
solving for z we get
z = 45°
put this value of z in Equation 5
x + ( 2 x 45° ) = 188°
or
x = 188° - 90° = 98°
hence , Angle COD = 98°














5 0
3 years ago
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