$\dfrac{4}{\sqrt[3]{4}}=\dfrac{4\cdot\sqrt[3]2}{\sqrt[3]{4}\cdot\sqrt[3]2}=\dfrac{4\sqrt[3]2}{\sqrt[3]{4\cdot2}}=\dfrac{4\sqrt[3]2}{\sqrt[3]8}=\dfrac{4\sqrt[3]2}{2}=2\sqrt[3]2$

$Use\ \sqrt[3]a\cdot\sqrt[3]b=\sqrt[3]{ab}$

7 0

3 years ago

At a school fundraiser, for every 12 boxes of chocalate sold a

meriva

Answer/Step-by-step explanation:

72/12=6

6x5=30

30 points.

5 0

1 year ago

Riccardo Frierson deposits $1,200 in savings account. The account pays a 3.5% annual interest rate. He makes no other deposits o

jonny [76]

Answer: 25

Step-by-step explanation:

7 0

2 years ago