Which product is negative?

. upper left chamber is enlarged, the risk of heart problems is increased. The paper "Left Atrial Size Increases with Body Mass

Sonbull [250]

Answer:

Part 1

(a) 0.28434

(b) 0.43441

(c) 29.9 mm

Part 2

(a) 0.97722

Step-by-step explanation:

There are two questions here. We'll break them into two.

Part 1.

This is a normal distribution problem healthy children having the size of their left atrial diameters normally distributed with

Mean = μ = 26.4 mm

Standard deviation = σ = 4.2 mm

a) proportion of healthy children have left atrial diameters less than 24 mm

P(x < 24)

We first normalize/standardize 24 mm

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (24 - 26.4)/4.2 = -0.57

The required probability

P(x < 24) = P(z < -0.57)

We'll use data from the normal probability table for these probabilities

P(x < 24) = P(z < -0.57) = 0.28434

b) proportion of healthy children have left atrial diameters between 25 and 30 mm

P(25 < x < 30)

We first normalize/standardize 25 mm and 30 mm

For 25 mm

z = (x - μ)/σ = (25 - 26.4)/4.2 = -0.33

For 30 mm

z = (x - μ)/σ = (30 - 26.4)/4.2 = 0.86

The required probability

P(25 < x < 30) = P(-0.33 < z < 0.86)

We'll use data from the normal probability table for these probabilities

P(25 < x < 30) = P(-0.33 < z < 0.86)

= P(z < 0.86) - P(z < -0.33)

= 0.80511 - 0.37070 = 0.43441

c) For healthy children, what is the value for which only about 20% have a larger left atrial diameter.

Let the value be x' and its z-score be z'

P(x > x') = P(z > z') = 20% = 0.20

P(z > z') = 1 - P(z ≤ z') = 0.20

P(z ≤ z') = 0.80

Using normal distribution tables

z' = 0.842

z' = (x' - μ)/σ

0.842 = (x' - 26.4)/4.2

x' = 29.9364 = 29.9 mm

Part 2

Population mean = μ = 65 mm

Population Standard deviation = σ = 5 mm

The central limit theory explains that the sampling distribution extracted from this distribution will approximate a normal distribution with

Sample mean = Population mean

¯x = μₓ = μ = 65 mm

Standard deviation of the distribution of sample means = σₓ = (σ/√n)

where n = Sample size = 100

σₓ = (5/√100) = 0.5 mm

So, probability that the sample mean distance ¯x for these 100 will be between 64 and 67 mm = P(64 < x < 67)

We first normalize/standardize 64 mm and 67 mm

For 64 mm

z = (x - μ)/σ = (64 - 65)/0.5 = -2.00

For 67 mm

z = (x - μ)/σ = (67 - 65)/0.5 = 4.00

The required probability

P(64 < x < 67) = P(-2.00 < z < 4.00)

We'll use data from the normal probability table for these probabilities

P(64 < x < 67) = P(-2.00 < z < 4.00)

= P(z < 4.00) - P(z < -2.00)

= 0.99997 - 0.02275 = 0.97722

Hope this Helps!!!

7 0

3 years ago

Bill's recipe for onion soup call for 4.0lb of thinly sliced onions. If an onion has an average mass of 115g, how many onions do

musickatia [10]

Answer:

1. $16\ onions$

2. $4,040.91\ kg$

Step-by-step explanation:

1. You know that the average mass of an onion is 115 grams and Bill needs 4.0 pounds.

Then, since $1\ lb=453.592\ g$ , we can make the following conversion:

$(4.0\ lb)(\frac{453.592\ g}{1\ lb})=1,814.37\ g$

Then, the number of onions Bill needs is:

$(1,814.37\ g)(\frac{1\ onion}{115\ g})=15.77\ onions$ ≈ $16\ onions$

2. Since $1\ kg=2.20462\ lb$ , we can make the following conversion:

$(11\ lb)(\frac{1\ kg}{2.20462\ lb})=4.98\ kg$

Knowing that all the potatoes sold today at the store bring in $1,420 and 4.98 kilograms of potatoes is $1.75, we can calculate the amount of kilograms the grocery shoppers bought:

$(\$1,420)(\frac{4.98\ kg}{\$1.75})=4,040.91\ kg$

6 0

2 years ago

Which inequality is represented by this graph? <br>

erica [24]

Answer:

x > 4

Step-by-step explanation:

Because x is greater than 4

6 0

2 years ago

Oil leaked from a tank at a rate of r(t) liters per hour. the rate decreased as time passed, and values of the rate at two hour

Galina-37 [17]

The given data is
t, h: 0 2 4 6 8 10
r(t), L/h: 8.6 7.9 6.8 6.4 5.7 5.3

The lower and upper estimates for the total amount that leaked may be computed as the Left and Right Riemann sums.

The shape of the graph of r versus will determine which of the two sums yields an upper or lower sum.
The plot of the graph is shown below.

The Left Riemann sum is
Sl = 2*(8.6+7.9+6.8+6.4+5.7) = 70.8 L

The Right Riemann sum is
Sr = 2*(7.9+6.8+6.4+5.7+5.3) = 64.2 L

Answer:
The lower estimate for oil leakage is 64.2 L
The upper estimate for oil leakage is 70.8 L

4 0

3 years ago

Read 2 more answers

The volume of a cone is 88 pi cubic feet. Its height is 8 feet. Fatima is finding the radius of the cone. Her work is shown belo

lions [1.4K]

Answer: 10.00

Step-by-step explanation:

You had to multiply and divide and see what you get.

6 0

3 years ago

Read 2 more answers