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trasher [3.6K]
2 years ago
12

Please help me find the y-intercept! :(

Mathematics
1 answer:
zvonat [6]2 years ago
4 0
5 inches

Explanation: y = Mx + b, m is your slope (1/2), b is your y-intercept (5 inches)

Equation would be y= (1/2)x + 5
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Please help me..I’ll give good points and give BRAINLIEST!
Alinara [238K]

Answer:

It's the 3rd one

Step-by-step explanation:

5 0
2 years ago
At Pizza Pi, 52% of the pizzas made last week had extra cheese. If 13 pizzas had extra cheese, how many pizzas in all were made
kodGreya [7K]

Answer:

39

Step-by-step explanation:

i hope this help

5 0
2 years ago
A number Q has a remainder of 3 when divided by 5 and also has a remainder of 4 when divided by 8. What is the smallest value Q
coldgirl [10]
5555666689919374747373
6 0
3 years ago
How many home runs did each player hit the season
olya-2409 [2.1K]
Let Peter's hit be x and Alice's runs be y.
x = 2(y - 6) . . . (1)
x + y = 18 . . . (2)

Putting (1) into (2) gives,
2y - 12 + y = 18
3y = 18 + 12 = 30
y = 30/3 = 10
x = 2(10 - 6) = 2(4) = 8

Therefore, Peter hit 8 home runs and Alice hit 10 home runs.
3 0
3 years ago
La barbería El Caleño, tiene en promedio 120 clientes a la semana a
Luba_88 [7]

Queremos maximizar el precio de tal forma que los ingresos no disminuyan.

Ese maximo precio es: $14,040.6

Sabemos que actualmente el precio es:

p = $6,000

El número de clientes es:

C = 120

Actualmente los ingresos son el producto de esos dos números, es decir:

ingresos = $6,000*120 = $720,000

Ahora sabemos que por cada incremento de $700 en el precio, el número de clientes decrece en 10.

Entonces podemos escribir el número de clientes como una ecuación lineal.

C(p) = a*p + b

tal que tenemos dos puntos en esa linea:

($6,000, 120)

($6,700, 110)

La pendiente es:

a = \frac{110 - 120}{\$6,700 - \$6,000} = \frac{-10}{\$ 700}

Entonces tenemos:

C(p) = (-10/$700)*p + b

Sabemos que:

C($6,000) = 120 = (-10/$700)*$6,000 + b

                     120 = -85.71 + b

                     120 + 85.71 = b =

Entonces la ecuación lineal es:

C(p) = (-10/$700)*p + 205.71

Los ingresos serán dados por:

ingresos = C(p)*p = (-10/$700)*p^2 + 205.71*p

Y queremos maximizar p de tal forma que esto sea igual a lo que obtuvimos antes:

(-10/$700)*p^2 + 205.71*p = $720,000

Entonces debemos resolver la ecuación cuadratica:

(-10/$700)*p^2 + 205.71*p - $720,000 = 0.

Las soluciones son dadas por la formula de Bhaskara.

p = \frac{-205.71 \pm \sqrt{(205.71)^2 - 4*(-10/\$ 700)*\$ 720,000} }{2*(-10/\$ 700)} \\\\p = \frac{-205.71 \pm 195.45}{(-20/\$ 700)}

La solución de maximo valor es:

p = (-205.71 - 195.45)/(-20/$700) = $14,040.6

Sí quieres aprender más, puedes leer.

brainly.com/question/8926135

7 0
2 years ago
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