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2 years ago

What is the sum of -15 and -8 increased by 20?

Mathematics

1 answer:

natta225 [31]2 years ago

6 0

-15+-8
-15-8
-23+20
-3
This is your answer boiiii or giiirlll

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n 2000 the population of a small village was 2,400. With an annual growth rate of approximately 1.68%, compounded continuously,

Nitella [24]

Answer:

The population would be 3358

Step-by-step explanation:

Since, exponential growth function if the growth is compound continuously,

$A = Pe^{rt}$

Where,

P = initial population,

r = growth rate per period,

t = number of periods,

Given,

The population in 2000, P = 2,400,

Growth rate per year = 1.68% = 0.0168,

Number of years from 2000 to 2020, t = 20,

Thus, the population in 2020,

$A=2400 e^{0.0168\times 20}$

$=2400 e^{0.336}$

$= 3358.4136$

$\approx 3358$

6 0

3 years ago

Which of the following options best describes the function graphed below?

wolverine [178]

Nonlinear increasing

6 0

3 years ago

WILL GIVE BRAINLIEST IF CORRECT!!

vfiekz [6]

Answer:

$\displaystyle y=-0.927x+13.63$

Step-by-step explanation:

Simple Linear Regression

It a function that represents the relationship between two or more variables in a given data set. It uses the method of the least-squares regression line which minimizes the error between the estimate function and the real data.

Let's compute the best-fit line for the data

$x=\{1,5,6,12,15\}$

$y=\{14,11,4,2,1\}$

First, we find the sums

$\displaystyle \sum x=1+5+6+12+15=39$

$\displaystyle \sum y=14+11+4+2+1=32$

Then, we compute the averages values

$\displaystyle \bar{x}=\frac{39}{5}=7.8$

$\displaystyle \bar{y}=\frac{32}{5}=6.4$

We will also compute the sums of the cross-products and the sum of the squares

$\displaystyle \sum xy=(1)(14)+(5)(11)+(6)(4)+(12)(2)+(15)(1)=137$

$\displaystyle \sum x^2=1^2+5^2+6^2+12^2+15^2=1+25+36+144+225$

$\displaystyle \sum x^2=431$

We will compute Sxy and Sxx

$\displaystyle S_{xy}=\sum xy-\frac{\sum x\ \sum y}{n}$

$\displaystyle S_{xy}=137-\frac{(39)(32)}{5}$

$\displaystyle S_{xy}=-117.6$

$\displaystyle S_{xx}=\sum x^2-\frac{(\sum x)^2}{n}$

$\displaystyle S_{xx}=431-\frac{39}{5}^2=126.8$

The slope of the linear regression function is given by

$\displaystyle m=\frac{S_{xy}}{S_{xx}}=\frac{-117.6}{126.8}=-0.927$

The y-intercept ot the linear function is

$\displaystyle b=\bar{y}-b\bar{x}=6.4-(-0.927)(7.8)$

$\displaystyle b=13.63$

Thus the best-fit line is

$\displaystyle y=-0.927x+13.63$

The correct option is the last one

5 0

2 years ago

In care cadrane se afla graficul functiei ; f:(x)=121x

iragen [17]

Solución X = {0, 121}
espero que esto ayude

8 0

2 years ago

Find the midpoint of the line segment.

Alik [6]

Answer:

(1, 3)

Step-by-step explanation:

The first endpoint (the one on the left) is (-3, 2). The second endpoint (the one on the right) is (5, 4). To find the midpoint, find the middle of both x and y. To do that, add the values of x and y respectively and divide by 2:

for x-value of midpoint:

(x-value of first endpoint + x-value of second endpoint) / 2

= (-3 + 5) / 2

= 2 / 2

= 1

for y-value of midpoint

(y-value of first endpoint + y-value of second endpoint) / 2

= (2 + 4) / 2

= 6 / 2

= 3

8 0

3 years ago