Question

Hi can you help me please? help please question 4 and 5. The second photo shows that you need to do this task in the table. Help please❤)

Answer 1

It is often easy to work these problems if you can arrange the coins in equal groups. In cases where there are a few more or less of one than another, you can add or subtract the appropriate number of coins to make it come out even.

4. Subtracting 3 quarters ($0.75) Rudolph will have $6.50 and an equal number of nickels and quarters with twice as many dimes. That is, Rudolph can group his coins into groups consisting of 1 quarter, 1 nickel, and 2 dimes, for a total of $.50 per group. 6.50/0.50 = 13 groups will make up the revised total.

Rudolph has 13 nickels, 26 dimes, and 16 quarters.

5. Adding 2 dimes to the total will allow Andrea to group her coins into groups that have 1 quarter, 4 nickels, and 4 dimes. Each group is worth $0.85, and her revised total will be $2.55. That is, she has 2.55/0.85 = 3 groups of coins.

Andrea has 3 quarters, 12 nickels, and 10 dimes.

Answer 2

For 4, she will have 16Q, 13N, and 26D. For 5, she has 10d, 12n, and 3Q. I got these answers from guess and checking. In the table, put the words nickel, dime, and quarter above the totals. For value, put how much the coin across is worth in cents. For #of, put how many of that coin are there. Amount is the amount of coins times how much is worth. For totals, put how much all 3 of the values, # or coins, or total amount of money.