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3 years ago

Can an Isosceles be a(n) A.Equilateral B.Scalene C.Right

Mathematics

2 answers:

gizmo_the_mogwai [7]3 years ago

7 0

An Isosceles can be scalene or right depending on it shape and size

Advocard [28]3 years ago

7 0

C, because a right triangle can have 2 same angles which are 45 degrees in both angles and 90 degrees for the right angle itself

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45 miles in 40 minutes

charle [14.2K]

Hi there!

45 mi to 40 min = 1.125 mi per min

45 ÷ 40 = 1.124

Hope this helps!

8 0

3 years ago

Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select t

Pepsi [2]

Answer:

Step-by-step explanation:

Two lines are perpendicular if the first line has a slope of $m$ and the second line has a slope of $\frac{1}{-m}$ .

With this information, we first need to figure out what the slope of the line is that we're given, and then we can determine what the slope of the line we're trying to find is:

$5x - 2y = -6$

$-2y = -5x - 6$

$y = \frac{5}{2}x + 3$

We now know that $m = \frac{5}{2}$ for the first line, which means that the slope of the second line is $m = \frac{-2}{5}$ . With this, we have the following equation for our new line:

$y = \frac{-2}{5}x + C$

where $C$ is the Y-intercept that we now need to determine with the coordinates given in the problem statement, $(5, -4)$ :

$y = \frac{-2}{5}x + C$

$(-4) = \frac{-2}{5}(5) + C$

$-4 = -2 + C$

$C = -2$

Finally, we can create our line:

$y = \frac{-2}{5}x - 2$

$5y = -2x - 10$

$2x + 5y = -10$

8 0

3 years ago

Read 2 more answers

The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as

bija089 [108]

Answer:

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(score of the 36 golfers was between 70 and 71)

$\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}$

$P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%$