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m_a_m_a [10]
3 years ago
15

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the

Mathematics
2 answers:
VladimirAG [237]3 years ago
7 0

Answer:

\boxed{108\sqrt{3}\text{ in}^{2}}

Step-by-step explanation:

An apothem is a perpendicular drawn from the centre of the triangle to one of its sides.

The three apothems OD, OE, and OF divide  ∆ABC into six smaller congruent triangles.

1. Area of ∆OCD

CotOCD = OD/OC

cot30 = CD/6

√3 = CD/6

CD = 6√3

A= ½bh

A = ½ × 6√3 × 6 = 18√3  in²

2. Area of ∆ABC

A = 6 × area of ∆OCD = 6 × 18√3 = 108√3 in²

\text{The area of the triangle is }\boxed{108 \sqrt{3} \text{ in}^{2}}

Doss [256]3 years ago
7 0

Answer:

just had this question :/ 108√3

Step-by-step explanation:

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Does anyone understand how to do this
Lerok [7]

Answer:

Step-by-step explanation:

I understand it!  (But I'm a high school math teacher so it might be unfair!) ; )

Anyway you have 2 numbers.  You don't know what they are so we will call them x and y.  Our first statement says that these numbers multiply to equal 120.  So that first equation is

xy = 120

Our second statement says that they add to -22.  So that second equation is

x + y = -22

Now we need to find the 2 numbers.  We have 2 unknowns, x and y.  That means that we have to have 2 equations.  No more than 2 no less than 2.  Solve the first equation for y.  It doesn't matter which equation you pick and which variable you choose to solve for.  If you do the work correctly, you will get the correct answers either way.  Solving the first equation for y gives you:

y=\frac{120}{x}

Now tht we have a value for y, we can use the substitution property of equality to sub that value into the second equation for y:

x+\frac{120}{x}=-22

Instead of finding a common denominator, we are going to eliminate x in the denominator altogether.  Do this by multiplying everything by x to get

x^2+120=-22x

Get everything on one side of the equals sign and factor:

x^2+22x+120=0

Because 12 * 10 = 120 and 12 + 10 = 22, our factors are 12 and 10:

x^2+12x+10x+120=0

Use factoring by grouping now.  

(x^2+12x)+(10x+120)=0

From the first set of parenthesis you can factor out an x, and from the second set you can factor out a 10:

x(x + 12) + 10(x + 12) = 0

Now factor out the common x + 12 to get a factored quadratic:

(x + 12)(x + 10) = 0

By the Zero Product Property, either x + 12 = 0 or x + 10 = 0.  Solving both for x gives you x = -12 or x = -10.

If x = -12, then

-12 + y = -22 so

y = -10

If x = -10, then

-10 + y = -22 so

y = -12.

The combinations of x and y are:

If x = -12, y = 10

If x = -10, y = -12

It doesn't matter which one is which.  They are not asking you to specifically define x and y.  They are asking you to find the numbers, and you did!

6 0
3 years ago
Please solve for x will mark brainliest answer
inna [77]

Answer:

x ≥ - 8

Step-by-step explanation:

Given

\frac{x}{2} ≥ - 4

Multiply both sides by 2 to eliminate the fraction

x ≥ - 8

7 0
3 years ago
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Question: A box of chocolates contains square chocolates, which weigh 10 g each, and round chocolates, which weigh 8 g each. The
Viktor [21]

Answer: the box contained 9 square chocolates and 15 round chocolates.

Step-by-step explanation:

Let x represent the number of square chocolates contained in the box.

Let y represent the number of round chocolates contained in the box.

The box of chocolates contains square chocolates, which weigh 10g each and round chocolates which weigh 8g each. The combined weight of all the chocolates is 210g. It means that

10x + 8y = 210- - - - - - - - - - -1

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y = 2x - 3

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26x = 234

x = 234/26

x = 9

y = 2x - 3 = 2 × 9 - 3

y = 18 - 3

y = 15

3 0
3 years ago
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