<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>
Out of the following given choices;
a) The amount of oxygen produced
b) The rate of ATP synthesis by ATP synthase in the chloroplast
c) The rate at which NADPH is produced
d) The rate at which the protons are transported into the thylakoid
The answer is; A
The photosystem captures energy from sunlight and uses it to split a water molecule. After splitting the water molecule (by taking an electron), the protein complex transports the electron to plastoquinone. The splitting of water molecules results in evolving of oxygen molecules. The hydrogen is what is used to reduce carbon dioxide to glucose.
Answer:
The doldrums are commonly found around the equator. The doldrums are an area characterized by calm monotonous weather.
Predator is an animal hunt.The prey is the animal that is being eaten by other animals. if there a lots of predators and few preys.the predators will compete for food