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juin [17]
4 years ago
14

Three tiny charged metal balls are arranged on a straight line. The middle ball is positively charged and the two outside balls

are negatively charged. The two outside balls are separated by 20 cm and the middle ball is exactly halfway in between. (HINT: Draw a picture; in your picture, the distance between the two outermost balls should be 20 cm.) The absolute value of the charge on each ball is the same, 1.12 μCoulombs (the meaning of μ, which is read as "micro", is 10-6). Give your answers in newtons.
(a) What is the magnitude of the attractive force on either outside ball due ONLY to the positively-charged middle ball? N
(b) What is the magnitude of the repulsive force on either outside ball due ONLY to the other outside ball? N
(c) What is the magnitude of the net force on either outside ball? N

Physics
1 answer:
Sedbober [7]4 years ago
4 0

Answer:

a)

The magnitude of the attractive force is 14.29N

b)

The magnitude of the repulsive force is 0.357N

c)

The magnitude of the net force is 0N

Explanation:

The explanation is shown on the first and second uploaded image

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3 years ago
Water enters a cylindrical tank through two pipes at rates of 250 and 100 gal/min. If the level of the water in the tank remains
tester [92]

Answer:

The total amount of water that enters the tank is:

250 gal/min + 100 gal/min = 350gal/min.

Then, if the level of the water remains constant, this means that the water leaves the tank at a rate of 350gal/min.

We know that the diameter of the pipe is 8 inches, then the area of the pipe is:

A = pi*(d/2)^2 = 3.14*(4in)^2 = 50.24in^2

now, the flow can be calculated as:

Q = v*A = (velocity*area)

if we want to write our velocity in inches per minute, then we need to write the entering flow in cubic inches:

1 gallon = 231 in^3

then:

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Then the water that leaves the tank must be the same amoun, we have:

Q = 80,850 in^3/min. = v*A = v*50.24in^2

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3 0
4 years ago
In a science fiction novel two enemies, Bonzo and Ender, are fighting in outer spce. From stationary positions, they push agains
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Answer:

2.461

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Mass of Ender =m2

When they push eachother from stationary position

Initial velocity of Bonzo = Vib=0 m/s

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Initial velocity of Ender = Vie= 0 m/s

Final velocity of Ender = Vfe= -3.1 m/s

We know initial momentum = final momentum

==> m1Vib+m2Vie = m1Vfb+m2Vfe

==> 0+0= m1×1.3 +m2×(-3.1)

==> 1.3m1-3.1m2=0

==> 1.3 m1 = 3.2 m2

==> m1/m2 = 3.2/1.3

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6 0
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NeTakaya
For this problem, the working equation should be used from the Beer's Law:

A = ∈lc,
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C = 9.27</span>×10⁻⁶ M
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