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satela [25.4K]
3 years ago
7

Give an example of Newton's second law in everyday life?

Physics
1 answer:
Marat540 [252]3 years ago
7 0
That’s the acceleration law! This would be a good example of inertia! When in a car, if the brakes are pressed immediately, the passengers will launch forward since their bodies are still in motion!
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8
aev [14]
OD because Boyle’s law specifically states
4 0
3 years ago
a dump truck travels 70mph for 3 hours, then for 20mph for another 2 hours in the same direction. what is the average speed the
Dmitry_Shevchenko [17]

Answer:

the average speed of the car is 170 mph.

Explanation:

Given;

initial speed, u = 70 mph

time of motion, t₁ = 3 hours

final speed, v = 20 mph

time of motion, t₂ = 2 hours

The average speed of the car is calculated as;

v' = \frac{70(3) - 20(2)}{3-2} \\\\v' = 170 \ mph

Therefore, the average speed of the car is 170 mph.

8 0
3 years ago
The mass of a moving object increases, but its speed stays the same. What happens to the kinetic energy of the object as a resul
ozzi
The correct answer is 
B It increases.

In fact, the kinetic energy of a moving object is given by
K= \frac{1}{2}mv^2
where m is the mass of the object and v is its speed. We see that the kinetic energy is proportional to the mass and proportional to the square of the speed: in this problem, the speed of the object remains the same, while its mass increases, therefore the kinetic energy will increase as well.
5 0
4 years ago
Read 2 more answers
A box is placed on a 30o frictionless incline. What is the acceleration of the box as it slides down the incline
balandron [24]

Answer:

<em>2.78m/s²</em>

Explanation:

Complete question:

<em>A box is placed on a 30° frictionless incline. What is the acceleration of the box as it slides down the incline when the co-efficient of friction is 0.25?</em>

According to Newton's second law of motion:

\sum F_x = ma_x\\F_m - F_f = ma_x\\mgsin\theta - \mu mg cos\theta = ma_x\\gsin\theta - \mu g cos\theta = a_x\\

Where:

\mu is the coefficient of friction

g is the acceleration due to gravity

Fm is the moving force acting on the body

Ff is the frictional force

m is the mass of the box

a is the acceleration'

Given

\theta = 30^0\\\mu = 0.25\\g = 9.8m/s^2

Required

acceleration of the box

Substitute the given parameters into the resulting expression above:

Recall that:

gsin\theta - \mu g cos\theta = a_x\\

9.8sin30 - 0.25(9.8)cos30 = ax

9.8(0.5) - 0.25(9.8)(0.866) = ax

4.9 - 2.1217 = ax

ax = 2.78m/s²

<em>Hence the acceleration of the box as it slides down the incline is 2.78m/s²</em>

5 0
3 years ago
How strong is the electric field between the plates of a 0.86 µf air-gap capacitor if they are 2.0 mm apart and each has a char
Gala2k [10]
The electric field between the plates is equal to the potential difference across the plates divided by the separation of the plates.
The potential difference across the plates is equal to the charge stored divided by the capacitance.
7 0
3 years ago
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