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Free_Kalibri [48]
3 years ago
14

An object in simple harmonic motion has an amplitude of 0.360 m and an oscillation period of 0.620 s. Determine the maximum spee

d of the motion.
Physics
1 answer:
steposvetlana [31]3 years ago
5 0

Answer:

3.648 m/s

Explanation:

Data provided in the question:

Amplitude, A = 0.360 m

oscillation period, T = 0.620 s

The maximum speed of the motion, V = A × ω

where,

ω = Angular speed

also,

ω = (2π) / T

on substituting the respective values, we get

ω = (2π) / 0.620

or

ω = 10.134 rad / s

therefore,

V = 0.360 × 10.134 = 3.648 m/s

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(Figure 1) shows the angular-velocity-versus-time graph for a particle moving in a circle. How many revolutions does the object
Travka [436]

Answer: 10.34

Explanation:

Given

\omega -t graph for a particle is given

angle turned by the particle in radians is given by the area under \omega -t graph

The area is given by

A=20\times (2-0)+10(4-2)+\dfrac{1}{2}\times (20-10)\times (3-2)\\A=40+20+5=65\ rad

Revolutions(N) made by the object is given by

N=\dfrac{65}{2\pi }=10.34

4 0
2 years ago
A box is dropped onto a conveyor belt moving at 3.2 m/s. If the coefficient of friction between the box and the belt is 0.28, ho
Lemur [1.5K]

Answer:

t = 1.16 s.

Explanation:

Given,

speed of conveyor belt, v = 3.2 m/s

coefficient of friction,f = 0.28

Using newton second law

f = ma

and we also know that frictional force

f = μ N

f = μ m g

equating both the force equation

a = μ g

a = 0.28 x 9.81

a = 2.75 m/s²

Using Kinematic equation

v = u + at

3.2 = 0 + 2.75 x t

t = 1.16 s.

Time taken by the box to move without slipping is 1.16 s.

6 0
3 years ago
At the race track, one race car starts its engine with a resulting intensity level of 104.0 dB at point P. Then 6 more cars star
dem82 [27]

To solve the problem it is necessary to apply the concepts related to sound intensity. The most common approach to sound intensity measurement is to use the decibel scale:

\beta (dB) = 10log_{10}(\frac{I}{I_0})

Where,

I_0 = 1*10^{-12} is a reference intensity. It is the lowest or threshold intensity of sound a person with normal hearing can perceive at a frequency of 1000 Hz.

I = Sound intensity

Our values are given by,

\beta = 104dB

\#Autos = 7

For each auto the intensity would be,

104 = 10log\frac{I}{1*10^{-12}}

10.4= log_{10} (\frac{I}{10^{-12}})

10^{10.4}*10^{-12}=I

I = 0.02511W/m^2

Therefore the sound intesity for the 7 autos is

I= 7* 0.02511

I = 0.1748W/m^2

The sound level for the 7 cars in dB is

\beta (dB) = 10log_{10}(\frac{0.1748}{1*10^{-12}})

\beta (dB) = 112.42dB

8 0
3 years ago
A plumber is going to put two pipes in a wall, one in front and one in back. The pipes will be touching once they are installed.
beks73 [17]

Answer:

They become the same exact tempature

Explanation:

Since they got connected it should be the same.

8 0
3 years ago
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OlgaM077 [116]

Answer:

I don't know but I will try:

because the red color from the density column.

8 0
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