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FromTheMoon [43]
3 years ago
10

Starting at sea level, a submarine descended at a constant rate to a depth of − 4/5 mile relative to sea level in 3 minutes.

Mathematics
2 answers:
Jobisdone [24]3 years ago
5 0
If it were 4 then it would be 1 1/3 for one minute
igomit [66]3 years ago
4 0

Answer:

\texttt{Submarine's depth relative to sea level after the first minute = }-\frac{4}{15} miles

Step-by-step explanation:

Starting at sea level, a submarine descended at a constant rate to a depth of −4/5 mile relative to sea level in 3 minutes.

Total time = 3 minutes

[tex]\texttt{Total depth descended in 3 minutes = }-\frac{4}{5}miles[/tex]

We need to find what was the submarine's depth relative to sea level after the first minute,

\texttt{Depth descended in per minute = }-\frac{\frac{4}{5}}{3}=-\frac{4}{15}miles

\texttt{Submarine's depth relative to sea level after the first minute = }-\frac{4}{15}\times 1=-\frac{4}{15} miles\\\\\texttt{Submarine's depth relative to sea level after the first minute = }-\frac{4}{15} miles

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Answer:

8 sand bags can be carried along.

Step-by-step explanation:

First you want to subtract 300-140. That subtracts the pilots weight giving you the maximum weight capacity left. (160) Then you want to divide 160 (the weight that can be carried) by 20 (the weight of the sand bags) after doing that you will get 8. And that is how i got 8 sand bags as my answer.

7 0
3 years ago
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An electronic device factory is studying the length of life of the electronic components they produced. The manager selects two
Temka [501]

Answer:

The confidence interval will be given by:

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For a confidence level of x%, z is the value in the z-table that has a pvalue of 1 - \frac{1 - z}{2}

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In the context of this problems:

It means that the sampling distributions of the sample mean of 500 components will be approximated normal, with mean 200,000 and standard deviation s = \frac{1000}{\sqrt{500}} = 44.72

To build the confidence interval:

The confidence interval for the average length of life of the electronic components they produced will be given by:

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3 0
3 years ago
G(x)=x+1<br> is it inverse
melisa1 [442]

Let y = G(x)

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Let y = f^(-1) x...INVERSE FUNCTION NOTATION.

ANSWER: f^(-1)x = x - 1

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I have this same problem
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3 years ago
Help me please- the fraction is 5/2.
Nostrana [21]

Answer:

Step-by-step explanation:10.8

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