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3 years ago

Starting at sea level, a submarine descended at a constant rate to a depth of − 4/5 mile relative to sea level in 3 minutes.

Mathematics

2 answers:

Jobisdone [24]3 years ago

5 0

If it were 4 then it would be 1 1/3 for one minute

igomit [66]3 years ago

4 0

Answer:

$\texttt{Submarine's depth relative to sea level after the first minute = }-\frac{4}{15} miles$

Step-by-step explanation:

Starting at sea level, a submarine descended at a constant rate to a depth of −4/5 mile relative to sea level in 3 minutes.

Total time = 3 minutes

$[tex]\texttt{Total depth descended in 3 minutes = }-\frac{4}{5}miles$ [/tex]

We need to find what was the submarine's depth relative to sea level after the first minute,

$\texttt{Depth descended in per minute = }-\frac{\frac{4}{5}}{3}=-\frac{4}{15}miles$

$\texttt{Submarine's depth relative to sea level after the first minute = }-\frac{4}{15}\times 1=-\frac{4}{15} miles\\\\\texttt{Submarine's depth relative to sea level after the first minute = }-\frac{4}{15} miles$

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Step-by-step explanation:

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Answer:

A² - 6A + 11 I = $\left[\begin{array}{ccc}0&0\\0&0\end{array}\right]$

Step-by-step explanation:

Given the matrix

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

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