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3 years ago

Starting at sea level, a submarine descended at a constant rate to a depth of − 4/5 mile relative to sea level in 3 minutes.

Mathematics

2 answers:

Jobisdone [24]3 years ago

5 0

If it were 4 then it would be 1 1/3 for one minute

igomit [66]3 years ago

4 0

Answer:

$\texttt{Submarine's depth relative to sea level after the first minute = }-\frac{4}{15} miles$

Step-by-step explanation:

Starting at sea level, a submarine descended at a constant rate to a depth of −4/5 mile relative to sea level in 3 minutes.

Total time = 3 minutes

$[tex]\texttt{Total depth descended in 3 minutes = }-\frac{4}{5}miles$ [/tex]

We need to find what was the submarine's depth relative to sea level after the first minute,

$\texttt{Depth descended in per minute = }-\frac{\frac{4}{5}}{3}=-\frac{4}{15}miles$

$\texttt{Submarine's depth relative to sea level after the first minute = }-\frac{4}{15}\times 1=-\frac{4}{15} miles\\\\\texttt{Submarine's depth relative to sea level after the first minute = }-\frac{4}{15} miles$

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(2) the second function g(x)
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∴ The average rate of g = $\frac{g(2 \pi)-g( \frac{3 \pi}{2} )}{2 
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(3) the third function h(x) = 6 sin x +1
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By comparing the results, The <span>function which has the greatest rate of change is h(x)
</span>

So, the correct answer is option <span>C) h(x)</span>

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