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madam [21]
3 years ago
6

Emely has 25 onions and 14 peppers that she grew in her garden. homw many more oinons does she have that peppers

Mathematics
1 answer:
stiks02 [169]3 years ago
4 0

Answer:

11

Step-by-step explanation:

<u><em>SUBTRACT</em></u>

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3. In the figure below, i ll k and m23 = 82º. Find the measurements of each remaining
REY [17]

Answer:

the measure of all angles are :

  • m 3 = 82°
  • m 2 = 82°
  • m 6 = 82°
  • m 7 = 82°
  • m 8 = 98°
  • m 1 = 98°
  • m 5 = 98°
  • m 4 = 98°

<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

3 0
3 years ago
Just ignore ABCD but can someone help me with E AND G plzzz
Lelechka [254]

Answer:

due \: to \: vertical \: opposite \: angel \:  \\ 78 = x   - 32 \\ 78  + 32 = x \\ 110 = x \\  \\ ....................................... \\ 2h + 44 = 126 \\ 2h = 126 - 44 \\ 2h = 82 \\ h = 41

4 0
3 years ago
Mark is in training for a bicycle race. He needs to ride 50 km a week as part of his training. He rode 18.23 km on Monday and 13
konstantin123 [22]
The answer is B-about 18km


This is because you round 18.23 to 18km


then you round 13.94 to 14km


you add these rounded numbers together


you take it away from 50km


the answer would then me 18km


but it be ABOUT because that was only a rough estimate because it was rounded
5 0
3 years ago
Read 2 more answers
The difference between two positive integers is 44. if the smaller is added to the square of the larger, the sum is 376376. find
pochemuha

Let a be the bigger number and b the smaller.


So a-b=44


and a^2+b=376376


(44+b)^2+b=376376

b^2+89b -374440=0


Solve for b and you get a. Are you sure it is 376376 not 376?

5 0
3 years ago
Use complete sentences to describe why √-1 ≠ -√1
tekilochka [14]

Well let's say that to compare these two numbers, we have to start with the definition first.

<u>D</u><u>e</u><u>f</u><u>i</u><u>n</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u>

\displaystyle \large{ {y}^{2}  = x} \\  \displaystyle \large{ y =  \pm  \sqrt{x} }

Looks like we can use any x-values right? Nope.

The value of x only applies to any positive real numbers for one reason.

As we know, any numbers time itself will result in positive. No matter the negative or positive.

<u>D</u><u>e</u><u>f</u><u>i</u><u>n</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>I</u><u>I</u>

\displaystyle \large{  {a}^{2}  = a \times a =  |b| }

Where b is the result from a×a. Let's see an example.

<u>E</u><u>x</u><u>a</u><u>m</u><u>p</u><u>l</u><u>e</u><u>s</u>

\displaystyle \large{  {2}^{2}  = 2 \times 2 = 4} \\  \displaystyle \large{  {( - 2)}^{2}  = ( - 2) \times ( - 2) =  | - 4|  = 4}

So basically, their counterpart or opposite still gives same value.

Then you may have a question, where does √-1 come from?

It comes from this equation:

\displaystyle \large{   {y}^{2}  =  - 1}

When we solve the quadratic equation in this like form, we square both sides to get rid of the square.

\displaystyle \large{   \sqrt{ {y}^{2} } =   \sqrt{ - 1}  }

Then where does plus-minus come from? It comes from one of Absolute Value propety.

<u>A</u><u>b</u><u>s</u><u>o</u><u>l</u><u>u</u><u>t</u><u>e</u><u> </u><u>V</u><u>a</u><u>l</u><u>u</u><u>e</u><u> </u><u>P</u><u>r</u><u>o</u><u>p</u><u>e</u><u>r</u><u>t</u><u>y</u><u> </u><u>I</u>

\displaystyle \large{  \sqrt{ {x}^{2}  } =  |x|  }

Solving absolute value always gives the plus-minus. Therefore...

\displaystyle \large{  y =   \pm \sqrt{ - 1}  }

Then we have the square root of -1 in negative and positive. But something is not right.

As I said, any numbers time itself of numbers squared will only result in positive. So how does the equation of y^2 = -1 make sense? Simple, it doesn't.

Because why would any numbers squared result in negative? Therefore, √-1 does not exist in a real number system.

Then we have another number which is -√1. This one is simple.

It is one of the solution from the equation y^2 = 1.

\displaystyle \large{   {y}^{2}  = 1} \\  \displaystyle \large{    \sqrt{ {y}^{2} }  =  \sqrt{1} } \\  \displaystyle \large{  y  =  \pm  \sqrt{1} }

We ignore the +√1 but focus on -√1 instead. Of course, we know that numbers squared itself will result in positive. Since 1 is positive then we can say that these solutions exist in real number.

<u>C</u><u>o</u><u>n</u><u>c</u><u>l</u><u>u</u><u>s</u><u>i</u><u>o</u><u>n</u>

So what is the different? The different between two numbers is that √-1 does not exist in a real number system since any squared numbers only result in positive while -√1 is one of the solution from y^2 = 1 and exists in a real number system.

5 0
3 years ago
Read 2 more answers
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