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2 years ago

Can someone explain this pleaae

Mathematics

2 answers:

Angelina_Jolie [31]2 years ago

8 0

i think the answer is but i am not a 100%
5.41853992195

almond37 [142]2 years ago

8 0

Note that when adding logs of the same base you multiply the insides of the log. Therefore:
㏒8(2)+log8(4x²)=log8(8x²)
log8(8x²)=1
8=8x²
x=√1, x=1,x=-1

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You need to count all the loaves of bread in the front area. There are 22 loaves of white bread , 17 loaves of wheat bread , and

pickupchik [31]

This is easy first do 22+17=39
next do 39+19=58

3 0

2 years ago

Read 2 more answers

Two partners agree to invest equal amounts in their business. One will contribute $10,000 immediately. The other plans to contr

krek1111 [17]

Answer:

She should contribute $ 8369.38 ( approx )

Step-by-step explanation:

Let P be the amount invested by the other partner,

∵ The amount formula in compound interest,

$A=P(1+\frac{r}{n})^{nt}$

Where,

r = annual rate,

n = number of compounding periods in a year,

t = number of years,

Here, r = 9% = 0.09, n = 4 ( quarters in a year ), t = 2 years,

Then the amount after 2 years,

$A = P(1+\frac{0.09}{4})^{8}$

According to the question,

A = $ 10,000,

$P(1+\frac{0.09}{4})^{8}= 10000$

$P(1+0.0225)^8 = 10000$

$\implies P = \frac{10000}{1.0225^8}\approx \$ 8369.38$

6 0

2 years ago

Determine if the sequence (cosn/ n) converges or diverges. tell if it is absolutely or conditionally convergent

nevsk [136]

. The series is divergent. To see this, first observe that the series ∑ 1/kn for n = 1 to ∞ is divergent for any integer k ≥ 2.

Now, if we pick a large integer for k, say k > 100, then for nearly all integers n it will be true that 1 > cos(n) > 1/k. Therefore, since ∑ 1/kn is divergent, ∑ cos(n)/n must also be divergent The *summation* is divergent, but the individual terms converge to the number 0.by comparison test since cosn/n <= 1/n is convergent and 1/n is divergent by harmonic series so the series is conditionally converget

4 0

2 years ago

Liliana wants to determine the height of an enlarged photo that she plans to frame. The original photo was 11 inches wide by 14

vova2212 [387]

For this case, the first thing we must do is find the scale factor.

For this, we use one of the dimensions. We will use the width of the photo.

We have then:

$k = \frac {132} {11}\\k = 12$