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ELEN [110]
3 years ago
6

Is the answers i picked right?

Mathematics
1 answer:
Ksivusya [100]3 years ago
8 0
Half right. The discriminate is whats under the square root in the quadratic equation, so when it's negative you get 2 complex conjugate roots. It's the +/- before it that gives one root for + and one root for -
2 roots, non-real
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(Use the Distributive Property to find an equivalent expression)<br> 2(3x-7y) = ?
IRINA_888 [86]

Answer:

(7y-3x)2

Step-by-step explanation:

It's the same thing but backwards

I hope this helps

6 0
2 years ago
Integer questions. Thank you!
andrezito [222]
3. We can see that
1+100=101
2+99=101
3+98=101
.................
and so on
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Z=101×50=5050
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1-2=-1
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4 0
3 years ago
Find the number that makes the ratio equivalent to 5:6.<br> :66
choli [55]

Answer:

55 - you multiplied 6 by 11 to get 66 so you multiply by 5 by 11 to get 55.

4 0
2 years ago
Ron is paid $1,500 every month plus an additional $100 bonus for every tractor he sells, x Which equation represents the total a
melamori03 [73]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A city council consists of seven Democrats and five Republicans. If a committee of four people is selected, find the probability
Hoochie [10]

Answer:

The probability  of selecting two Democrats and two Republicans is 0.4242.

Step-by-step explanation:

The information provided is as follows:

  • A city council consists of seven Democrats and five Republicans.
  • A committee of four people is selected.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

{n\choose k}=\frac{n!}{k!\times (n-k)!}

Compute the number of ways to select four people as follows:

{12\choose 4}=\frac{12!}{4!\times (12-4)!}=495

Compute the number of ways to selected two Democrats as follows:

{7\choose 2}=\frac{7!}{2!\times (7-2)!}=21

Compute the number of ways to selected two Republicans as follows:

{5\choose 2}=\frac{5!}{2!\times (5-2)!}=10

Then the probability  of selecting two Democrats and two Republicans as follows:

P(\text{2 Democrats and 2 Republicans})=\frac{21\times 10}{495}=0.4242

Thus, the probability  of selecting two Democrats and two Republicans is 0.4242.

6 0
2 years ago
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