Answer:
y = x + 1
Step-by-step explanation:
The gradient of a line can be defined by the equation:
m (gradient) = (y1 – y2 ) ÷ (x1 – x2) ----> "1" and "2" should be in subscript
For (-7,-6) we use x2 and y2 (because this point can be anywhere along a line):
x2 = -7, y2 = -6
Plug these values into the formula above:
m = (y-(-6)) ÷ (x-(-7))
m = (y+6) ÷ (x+7)
At this stage, the equation can't be solved as there are two unknowns. Therefore, the gradient must be found another way. Two lines are parallel if they have the same gradient - in their y=mx+c equations, m will be equal.
x - y=7 is the line alluded to in the question. Rearranging this equation into the line equation format gives:
y = x-7 ---> The gradient (coefficient of x) is 1.
Therefore, the gradient of the other parallel line must also be 1.
This can be substituted into the previous equation to give:
1 = (y+6)÷(x+7)
x+7 = y+6
x+1 = y
Therefore, the answer is y=x+1
Answer: A. 70
Step-by-step explanation:
95 + 90 + 85 + 80 + 70 = 420, then divide that by 5 equals 84
Step-by-step explanation:
Clue: (I'm not giving the answer this is just clues) The word "absolute" helps you understand not to estimate so you want to get the RIGHT answer not the estimation.
Answer:
D. Triangle QRS is an isosceles triangle because QR = RS.
Step-by-step explanation:
Find the length of each side of the triangle using the formula for calculating the distance between two points.
D = √(x2-x1)²+(y2-y1)²
For side RS
R(0,0) and S(5, -3.322)
RS = √(5-0)²+(-3.322-0)²
RS = √25+11.035684
RS = √36.035684
RS = 6.0029
For side RQ
R(0,0) and Q(-3, -5.2)
RQ = √(-3-0)²+(-5.2-0)²
RQ = √9+27.04
RQ = √36.04
RQ = 6.0033
For side QS
Q(-3,-5.2) and S(5, -3.322)
QS = √(5+3)²+(-3.322+5.2)²
QS = √64+3.526884
QS = √67.526884
QS = 8.22
From the calculation it can be seen that RS=QR
Since the two sides f the triangle are equal, hence the triangle is an isosceles triangle. An isosceles triangle is a triangle that has two of its sides equal
2/5 I believe. Correct me if I am wrong
