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Contact [7]
3 years ago
14

The length of the sides of a triangle are three consecutive integers. If the perimeter is 87, find the dimensions of the triangl

e. Show all work.
Mathematics
2 answers:
nadezda [96]3 years ago
8 0
You can divide 87 by 3 which is 29, so each angle will be 29 degrees.
Since they are consecutive, that means they will all measure the same.

Hope this helps! :)
sashaice [31]3 years ago
5 0
X = smallest side length
x+1 = midsized side length
x+2 = largest side length

Add up the three sides. Set the sum equal to 87 and then solve for x
(x)+(x+1)+(x+2) = 87
(x+x+x) + (1+2) = 87
3x+3 = 87
3x = 87-3
3x = 84
x = 84/3
x = 28

If x = 28, then
x+1 = 28+1 = 29
x+2 = 28+2 = 30

So the triangle has the three sides: 28, 29, 30
Check: 28+29+30 = 87

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Answer:

y = 2 \cos(4x)  - 1 \\ when \: y = 0 \\  \cos(4x)  =  \frac{1}{2}  \\ 4x = 60 \\ x = 15 \\ when \: x = 0 \\ y = 2 - 1 = 1 \\ intercepts =  > (15, \: 0) \: and \: (0, \: 1) \\ midpoints : ( \frac{15 + 0}{2} , \:  \frac{0 + 1}{2} ) \\  = (7.5, \: 0.5) \\ gradient =  \frac{1 - 0}{0 - 15}  \\  =  -  \frac{1}{15}  \\ y = mx + c \\ at \: (7.5, \: 0.5) \\ 0.5 =  -  \frac{1}{15}  \times 7.5 + c \\ 0.5 =  - 0.5 + c \\ c = 1 \\  \therefore \: y =  -  \frac{1}{15} x + 1 \\  =  > 15y =  - x + 15

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3 years ago
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neither

Step-by-step explanation:

First differences are 3, 5, 7, 9, and the differences of these (2nd differences) are constant at 2. The degree of the polynomial function describing the sequence is equal to the number of the differences that are constant. Here, that is 2nd differences, so the sequences is described by a 2nd-degree (quadratic) polynomial.

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A.)129/7

Step-by-step explanation:

25/4 + 24/7 + 35/4

I will add the two with common denominator together first

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60/4   +24/7

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We need to get a common denominator of 7

15 *7/7  + 24/7

105/7  + 24/7

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Answer:

sorry but I don't know the answer

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3 years ago
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