To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer:
V = 
Step-by-step explanation:
Volume of a cone is:
Substitute values given:
V = 
V =
Answer:
Point D
Step-by-step explanation:
AD and CD are a line
The intersection of two lines is a point
The two lines intersect at point D
Answer:
B=-1
Step-by-step explanation:
Standard form is Ax+By=C.
In this case, Ax is x, By is 1/5y, and C is +2.
To isolate the 2 (the C), subtract x from both sides of the equation:
x+2=1/5y
-x -x
2=-x+1/5y.
Now, the value of B, the x value, is -1.
