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Ganezh [65]
3 years ago
6

Find the product (2x^2+tv)(3x^2-3tv)

Mathematics
1 answer:
vodka [1.7K]3 years ago
5 0
= 2x^2 * 3x^2 + - 2x^2 * 3tv + 3x^2tv -  3t^2v^2

=   6x^4 - 6x^2tv + 3x^2tv - 3t^2v^2

=  6x^4 - 3x^2tv - 3t^2v^2
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