All categories

3 years ago

Help!!!! f(x)=10x+3 g(x)= -7x-4

Mathematics

1 answer:

Gelneren [198K]3 years ago

8 0

Answer:

8x + 7

Step-by-step explanation:

You might be interested in

What is the distance between (-6,8) and (-3,9)?

yKpoI14uk [10]

The midpoint is: (-4.5,8.5)

3 0

3 years ago

Read 2 more answers

The endpoints of directed line segment PQ have coordinates of P(-7, -5) and Q(5,3). What are the coordinates of point A, on PQ,t

Kamila [148]

Answer:

Therefore the co-ordinate of the point A is (-4,-3)

Step-by-step explanation:

If A(x₁,y₁) and B(x₂,y₂) is divided by a point in ration m:n internally.

Then the co-ordinate of the point is $(\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_2}{m+n})$ .

Given two points are P(-7,-5) and Q(5,3).

A point A on PQ, that divides PQ into a ratio of 1:3.

Since the point A lies on the PQ.

Therefore it divides the line segment PQ internally.

Here x₁= -7,y₁= -5 , x₂= 5,y₂ =3, m=1,n=3

Therefore the co-ordinate of the point A is

$(\frac{5.1+(-7).3}{1+3},\frac{3.1+(-5).3}{1+3})$

$=(\frac{-16}{4},\frac{-12}{4})$

=(-4,-3)

6 0

3 years ago

Help me on number 24 plss

chubhunter [2.5K]

The animal that shows the fastest change is the horse. The animal that shows that slowest rate of change is the mouse.
We can use graphs to find the rate of chabge by comparing. From using only the beginning and ending of the data, we would be finding the average rate of change over the specified period of time.
I think yes, my answers are reasonable.

I hope this helps :)

7 0

3 years ago

Four lawn sprinkler heads are fed by a 1.9-cm-diameter pipe. The water comes out of the heads at an angle of 35° above the horiz

klemol [59]

Answer:

Step-by-step explanation:

Given:

Angle, θ = 35°

Vertical distance, Δx = 6 m

Diameter, d = 1.9 cm

= 0.019 m

When the water leaves the sprinkler, it does so at a projectile motion.

Therefore,

Using equation of motion,

(t × Vox) = 2Vo²(sin θ × cos θ)/g

= Δx = 2Vo²(sin 35 × cos 35)/g

Vo² = (6 × 9.8)/(2 × sin 35 × cos 35)

= 62.57

Vo = 7.91 m/s

Area of sprinkler, As = πD²/4

Diameter, D = 3 × 10^-3 m

As = π × (3 × 10^-3)²/4

= 7.069 × 10^-6 m²

V_ = volume rate of the sprinkler

= area, As × velocity, Vo

= (7.069 × 10^-6) × 7.91

= 5.59 × 10^-5 m³/s

Remember,

1 m³ = 1000 liters

= 5.59 × 10^-5 m³/s × 1000 liters/1 m³

= 5.59 × 10^-2 liters/s

= 0.0559 liters/s.

For the 4 sprinklers,

The rate at which volume is flowing in the 4 sprinklers = 4 × 0.0559

= 0.224 liters/s

Area of 1.9 cm pipe, Ap = πD²/4

= π × (0.019)²/4

= 2.84 × 10^-4 m²

Volumetric flowrate of the four sprinklers = 4 × 5.59 × 10^-5 m³/s

= 2.24 × 10^-4 m³/s

Velocity of the water, Vw = volumetric flowrate/area

= 2.24 × 10^-4/2.84 × 10^-4

= 0.787 m/s

7 0

3 years ago

Read 2 more answers

What is the weight of the plane with 81 gallons of fuel in its tanks?

JulijaS [17]

The weight of a plane with 81 gallons of fuel in the tank is about 44 tons

3 0

3 years ago