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Ipatiy [6.2K]
3 years ago
10

Describe the difference between Homogenous and Heterogenous mixtures.

Chemistry
2 answers:
KiRa [710]3 years ago
8 0

Answer: homogues mixture with 2 compound

Explanation:

zalisa [80]3 years ago
8 0

Answer:

,

Explanation:

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2H2 + O2 --> 2H2OHow many moles of hydrogen gas are needed to produce 120g of water?
wlad13 [49]
<h2>Answer:</h2>

6.67moles

<h2>Explanations:</h2>

Given the balanced chemical reaction between hydrogen and oxygen expressed as:

2H_2+O_2\rightarrow2H_2O

First, you need to calculate the moles of water produced.

\begin{gathered} \text{Moles}=\frac{Mass}{\text{Molar mass}} \\ \text{Moles of water=}\frac{120}{2(1)+16} \\ \text{Moles of water}=\frac{120}{18} \\ \text{Moles of water}=6.67\text{moles} \end{gathered}

Based on stochiometry, 2 moles of hydrogen produces 2 moles of water, hence the moles of hydrogen that will be needed to produce 120g of water is 6.67moles

6 0
1 year ago
A coffee cup calorimeter was used to measure the heat of solution, the change in enthalpy that occurs when a solid dissolves in
Akimi4 [234]

Answe5r:

Explanation:

4 0
4 years ago
What determines the amount of chemical energy a substance has?
tino4ka555 [31]
I believe amount of valence electrons 
3 0
3 years ago
How many electrons are in the outermost principal energy level of an atom of carbon in the ground state
Agata [3.3K]

Answer:

four electrons

Explanation:

Let us attempt to write the electronic configuration of carbon in the ground state. This electronic configuration will now be;

C- 1s2 2s2 2p2

The outermost principal energy level of carbon is the n=2 level which houses the 2s2 and 2p2, making a total of four electrons in the outermost principal energy level of an atom of carbon in the ground state.

5 0
3 years ago
Why does the excess of base used in these eliminations favor the E2 over the E1 mechanism for elimination
Alex787 [66]

Answer:

The base is involved in the rate determining step of an E2 reaction mechanism

Explanation:

Let us get back to the basics. Looking at an E1 reaction, the rate determining step is unimolecular, that is;

Rate = k [Carbocation] since the rate determining step is the formation of a carbonation.

For an E2 reaction however, the reaction is bimolecular hence for the rate determining step we can write;

Rate = k[alkyl halide] [base]

The implication of this is that an excess of either the alkyl halide or base will facilitate an E2 reaction.

Hence, when excess base is used, E2 reaction is favoured since the base is involved in its rate determining step. In an E1 reaction, the base is not involved in the rate determining step hence an excess of the base has no effect on an E1 reaction.

8 0
3 years ago
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