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vodomira [7]
2 years ago
10

Which description accurately represents a water molecule

Chemistry
1 answer:
inna [77]2 years ago
4 0

Answer:

The water molecule is comprised of two hydrogen (H) atoms and one oxygen atom,  oxygen atom has 8 electrons, and each H has 1 electron. The H atoms bond to the oxygen by sharing a pair of electrons in what is called a covalent bond. In each pair of shared electrons, one electron is contributed by the H (black) and one from the oxygen (red).

Explanation:

have a great day and please mark brainliest

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What is the density of an object that has a mass of 28.1g and a volume of 96.2mL? Select the correct answer below: 0.292g/mL 270
kakasveta [241]

Answer:

0.292 g/mL.

Explanation:

From the question given above, the following data were obtained:

Mass of object = 28.1 g

Volume of object = 96.2 mL

Density of object =..?

Density of an object is simply defined as the mass of the object per unit volume of the object. Mathematically, it can be expressed as:

Density = mass / volume

With the above formula, we can obtain the density of the object as follow:

Mass of object = 28.1 g

Volume of object = 96.2 mL

Density of object =..?

Density = mass / volume

Density = 28.1 / 96.2

Density of object = 0.292 g/mL

Thus the density of the object is 0.292 g/mL

3 0
3 years ago
Which type of compounds are likely to be nonconductors in their solid forms but conductors when they are mixed with water
Blizzard [7]
Ionic compounds. because when in solid form they are held firmly in place therefore they cannot move to conduct electric current.
8 0
3 years ago
When two atoms form a covalent bond, they share electrons from all of their orbitals. All of their orbitals, in turn, combine to
erma4kov [3.2K]

Answer:

It's false.

Explanation:

Molecular orbital theory states that the number of molecular orbitals is equal to the number of atomic orbitals that overlap. The lowest energy molecular orbital is formed when two atomic orbitals that are in phase overlap, forming a bonding molecular orbital. However, another molecular orbital is also formed, called an anti-binding orbital.

So if an "n" quantity of atomic orbitals is combined, an "n" quantity of molecular orbitals is formed.

Have a nice day!

8 0
3 years ago
In a nuclear reaction, which quantity is the same before and after the change?(1 point)
vivado [14]

Answer:In alpha decay, shown in Fig. 3-3, the nucleus emits a 4He nucleus, an alpha particle. Alpha decay occurs most often in massive nuclei that have too large a proton to neutron ratio. An alpha particle, with its two protons and two neutrons, is a very stable configuration of particles. Alpha radiation reduces the ratio of protons to neutrons in the parent nucleus, bringing it to a more stable configuration. Many nuclei more massive than lead decay by this method.

Consider the example of 210Po decaying by the emission of an alpha particle. The reaction can be written 210Po Æ 206Pb + 4He. This polonium nucleus has 84 protons and 126 neutrons. The ratio of protons to neutrons is Z/N = 84/126, or 0.667. A 206Pb nucleus has 82 protons and 124 neutrons, which gives a ratio of 82/124, or 0.661. This small change in the Z/N ratio is enough to put the nucleus into a more stable state, and as shown in Fig. 3-4, brings the "daughter" nucleus (decay product) into the region of stable nuclei in the Chart of the Nuclides.

In alpha decay, the atomic number changes, so the original (or parent) atoms and the decay-product (or daughter) atoms are different elements and therefore have different chemical properties.

Upper end of the Chart of the Nuclides

In the alpha decay of a nucleus, the change in binding energy appears as the kinetic energy of the alpha particle and the daughter nucleus. Because this energy must be shared between these two particles, and because the alpha particle and daughter nucleus must have equal and opposite momenta, the emitted alpha particle and recoiling nucleus will each have a well-defined energy after the decay. Because of its smaller mass, most of the kinetic energy goes to the alpha particle.

5 0
2 years ago
If 1.8 L of water is added to 2.5L of a 7.0 Molarity
liq [111]

Answer:

4.1 mol·L⁻¹

Explanation:

You are diluting the solution with water, so you can use the dilution formula

c₁V₁ = c₂V₂     Divide each side by V₂

 c₂ = c₁ × V₁/V₂

Data:

c₁ = 7.0 mol·L⁻¹; V₁ = 2.5 L

Water added = 1.5 L

Calculations:

(a) <em>New volume </em>

V₂ = 2.5 L + 1.8 L

     = 4.3 L

(b) <em>New concentration </em>

c₂ = 7.0 × 2.5/4.3

    = 7.0 × 0.581

    = 4.1 mol·L⁻¹

6 0
3 years ago
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