Ask question

Ask question

All categories

3 years ago

13

Hydrochloric acid has the chemical formula HCl. A certain quantity of hydrochloric acid has 2.39x1024 atoms. How many moles of h

ydrochloric acid is the sample?

1 answer:

nasty-shy [4]3 years ago

8 0

Answer: 3.97 moles HCl

Explanation: Solution:

2.39x10²⁴ atoms HCl x 1 mole HCl /

6.022x10²³ atoms HCl

= 3.97 moles HCl

You might be interested in

How many molecules of H2O are equivalent to 98.2 g of H2O

GREYUIT [131]

Answer:

Demo Mole Quantities

58.5g NaCl(mol/58.5g)(6.02 x 1023/mol) = 6.02 x 1023 Na

+

Cl21 pre-1982 pennies (after 1982 pennies are mostly zinc with copper coating)

63.5g Cu( mol/ 63.5g)(6.02 x 1023/mol) = 6.02 x 1023 Cu

19.0g Al (mol/27.0g)(6.02 x 1023/mol) = 4.24 x 1023 Al

Explanation:

3 0

3 years ago

For green plant cells, which are the substances that result from photosynthesis that are used in cellular respiration? A. oxygen

strojnjashka [21]

Answer:

B. oxygen and glucose

Explanation:

Oxygen for respiration and glucose for energy utilization

6 0

3 years ago

A student wants to know if the effect of gravity is the same on all objects. She follows these steps:

BartSMP [9]

Choose new balls (which is A I believe)

8 0

3 years ago

Find the theoretical oxygen demand for the

never [62]

Answer:

a) 213.3 mg/L

b) 62.61 mg/L

c) 0.0225 mg/L

Explanation:

Theoretical oxygen demand (ThOD)is essentially the amount of oxygen required for the complete degradation of a given compound into the final oxidized products

a) Given:

Concentration of acetic acid, $[CH3COOH]$ = 200 mg/L

$CH3COOH + 2O2 \rightarrow 2CO2 + 2H2O$

$ThOD = \frac{mass\ O2}{mass\ CH3COOH} * conc. CH3COOH$

Based on the reaction stoichiometry:

mass of $CH3COOH$ = 60 g

mass of $O2$ = 2(32) = 64 g

$ThOD = \frac{64 g}{60 g} * 200mg/L = 213.3 mg/L$

b) Given:

Concentration of ethanol, $[C2H5OH]$ = 30 mg/L

$C2H5OH + 3O2 \rightarrow 2CO2 + 3H2O$

$ThOD = \frac{mass\ O2}{mass\ C2H5OH} * conc. C2H5OH$

Based on the reaction stoichiometry:

mass of $C2H5OH$ = 46 g

mass of $O2$ = 3(32) = 96 g

$ThOD = \frac{96 g}{46 g} * 30mg/L = 62.61 mg/L$

c) Given:

Concentration of sucrose, $[C12H22O11]$ = 50 mg/L

$C12H22O11 + 12O2 \rightarrow 12CO2 + 11H2O$

$ThOD = \frac{mass\ O2}{mass\ C22H22O11} * conc. C12H22O11$

Based on the reaction stoichiometry:

mass of $C12H22O11$ = 342 g

mass of $O2$ = 12(32) = 384 g

$ThOD = \frac{384 g}{342 g} * 50mg/L = 0.0225 mg/L$

7 0

3 years ago

PLEASE HELP ITS DUE SOON AND I DONT UNDERSTAND

nadezda [96]

The answer is 137 grams boyyy

3 0

2 years ago