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Zinaida [17]
3 years ago
15

Suppose the circumference of a circle is 2 pi what is the area?

Mathematics
2 answers:
Olenka [21]3 years ago
5 0
C = 2 * pi * r

Plug in what we know:

2pi = 2 * pi * r

Divide 2 pi to both sides:

r = 1

(Remember, anything divided by itself is equal to 1)

A = pi * r^2

Plug in what we know:

A = pi * 1^2

A = pi * 1

A = 1 pi

So the area is '1 pi' or just 'pi'.
irina1246 [14]3 years ago
4 0
 <span>Circumference of a circle = 2 π r 

(where r is the radius) 

Area of a circle = π r^2 

(where r is the radius) 

you have to find the radius

C = 2π unit 
r = 1 unit 

Area = π square units 
</span>
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Is -2x-6=2x+6 no soulution
Olegator [25]

Answer:

No

Step-by-step explanation:

Let's solve your equation step-by-step.

−2x−6=2x+6

Step 1: Subtract 2x from both sides.

−2x−6−2x=2x+6−2x

−4x−6=6

Step 2: Add 6 to both sides.

−4x−6+6=6+6

−4x=12

Step 3: Divide both sides by -4.

−4x/−4 = 12/-4

=

x=−3

6 0
3 years ago
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Help please.<br><br><br> answer choices:<br> a)2/3<br> b)3/2<br> c)6/9<br> d)4/6
mr Goodwill [35]
The answer is It’s 3/2
7 0
3 years ago
What is 2+2?<br><br><br> i'm giving you points you should be thanking me
Nitella [24]

Answer:

2+2=4

Step-by-step explanation:

Thanks ig

7 0
3 years ago
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8th grade math . Pythagorran practice <br>​
Serhud [2]

The answers according to rows are:

  • ROW 1 : diameter of base = 10,  base area = 25π, volume of cylinder = 175π    volume of cone = \frac{175}{3}π
  • ROW 2 : base radius = 3, base area = 9π, height = 40/3, volume of cylinder = 120π
  • ROW 3 : base radius = 6, base diameter = 12, height = 4, volume of cylinder = 144π

<h3>What is mensuration?</h3>

Mensuration is an aspect of geometry that deals with measurement of volumes and area.

Analysis:

Row 1

Diameter of base = 2 x radius = 2 x 5 = 10

Base area = πr^{2} = π(5)^{2} = 25\pi

Volume of cylinder = base area x height = 25π x 7 = 175π

Volume of cone  = 1/3 x volume of cylinder = 175π/3

Row 2

Base radius = base diameter/2 = 6/2 = 3

Base area = πr^{2} = π(3)^{2} = 9π

Volume of cone = 1/3 x base area x height

base area x height  = 3 x volume of cone

base area x height = 3 x 40π

Height = 120π/9π = 40/3

Cylinder volume = 3 x cone volume = 3 x 40π = 120π

Row 3

Base area = πr^{2}

36π =  πr^{2}

r2 = \sqrt{36}

r = 6

Base diameter = 2 x 6 = 12

Volume of cone  = 1/3 x base area x height

48π = 1/3 x 36π x height

Height = 4

Cylinder volume = 3 x 48 = 144π

In conclusion,

ROW 1 : diameter of base = 10,  base area = 25π, volume of cylinder = 175π

volume of cone = \frac{175}{3}π

ROW 2 : base radius = 3, base area = 9π, height = 40/3, volume of cylinder = 120π

ROW 3 : base radius = 6, base diameter = 12, height = 4, volume of cylinder = 144π

Learn more about mensuration: brainly.com/question/18541562

#SPJ1

4 0
2 years ago
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MAXImum [283]
No, it is not a function.
Since all the lines have been drawn in the grid line do not have any connection between them even a point in common.
I hope this has been useful for you.
8 0
3 years ago
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